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Arlecino [84]
3 years ago
9

A high school student named David Merrell did a study of how music affects the ability of rats to run a maze. He trained 71 rats

to run a maze. Next he randomly divided the rats to three groups. Each group had 23 or 24 rats. For the next month, one group of rats listened all day to heavy metal music by the group Anthrax. One group listened all day to Mozart. One group never heard music. The rats ran the same maze three times a week for a month. The response variable is the time in seconds to complete the maze. By the end of the month he compared the average run time for each treatment group to the average run time for the control group. The Anthrax group was much slower at running the maze. The Mozart group was much faster. The differences are statistically significant at the 1% level. Run times are not heavily skewed in any group. What conclusion can we draw from these results?
Mathematics
1 answer:
ladessa [460]3 years ago
3 0
I don’t understand what you are saying...
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Step-by-step explanation:

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Solve: 4x - 2x + 6 = x + 12 A) x = 6 B) x = 2 C) no solution D) x = −6
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4x - 2x + 6 = x + 12

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The Eco Pulse survey from the marketing communications firm Shelton Group asked individuals to indicate things they do that make
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Answer:

a) There is a probability of 42% that the person will feel guilty for only one of those things.

b)There is a probability of 46% that a randomly selected person will not feel guilty for either of these reasons

Step-by-step explanation:

This probability problem can be solved by building a Venn like diagram for each probability.

I say that we have two sets:

-Set A, for those people that will feel guilty about wasting food.

-Set B, for those people that will feel guilty about leaving lights on when not in a room.

The most important information is that there is a .12 probability that a randomly selected person will feel guilty for both of these reasons. It means that P(A \cap B) = .12.

The problem also states that there is a .39 probability that a randomly selected person will feel guilty about wasting food. It means that P(A) = 0.39. The probability of a person feeling guilty for only wasting food is PO(A) = .39-.12 = .27.

Also, there is a .27 probability that a randomly selected person will feel guilty about leaving lights on when not in a room. So, the probability of a person feeling guilty for only leaving the lights on is PO(B) = 0.27-0.12 = 0.15.

a) What is the probability that a randomly selected person will feel guilty for either wasting food or leaving lights on when not in a room?

This is the probability that the person feels guilt for only one of those things, so:

P = PO(A) + PO(B) = 0.27 + 0.15 = 0.42 = 42%

b) What is the probability that a randomly selected person will not feel guilty for either of these reasons

The sum of all the probabilities is always 1. In this problem, we have the following probabilies

- The person will not feel guilty for either of these reasons: P

- The person will feel guilty for only one of those things:  PO(A) + PO(B) = 0.42

- The person will feel guilty for both reasons: PB = 0.12

So

`P + 0.42 + 0.12 = 1

P = 1-0.54

P = 0.46

There is a probability of 46% that a randomly selected person will not feel guilty for either of these reasons

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3 years ago
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