Thank you for posting you question here at brainly. Below is the solution:
1/97 = 1 / (100-3) = 1 / (xo + dx)
<span>so, you have now that </span>
<span>x = xo + dx, where x = 97, xo = 100, and dx = - 3. Recognizing that 3 << 100, we can write the Taylor expansion around xo </span>
<span>1/ (xo + dx) ~ 1/xo + d/dx(1/xo)dx = 1/xo + (-1/xo^2)dx </span>
<span>= 1/100 - (1/100^2) (-3) = 1/100 + 3/100^2 </span>
<span>= 1/100 + 3/10000 </span>
<span>= 0.01 + 0.0003 </span>
<span>= 0.0103 </span>
Answer:
six points for all this ? HAHAHAHAHA LFMAO
Step-by-step explanation:
1.772454 that’s what I got
Answer:
4 and 5
Step-by-step explanation:
n + 1 > 4
n > 4 - 1
n > 3
For the set { 1, 2 , 3 , 4, 5 }, 4 and 5 are greater than 3.
Hence, 4 and 5 makes the inequality n + 1 > 4 true.
