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Alex777 [14]
3 years ago
15

Classify the triangle. scalene equilateral isosceles

Mathematics
2 answers:
VMariaS [17]3 years ago
4 0









This is a scalene triangle
Nadya [2.5K]3 years ago
3 0

Answer:

The correct answer is A. Scalene.

Step-by-step explanation

Unlike the isosceles triangle, which is formed by two equal sides and one unequal; and the equilateral triangle, which is formed by three equal sides. The scalene triangle is formed by 3 sides of different measures, for this reason and according to the image that shows a triangle with the left side of 3, the bottom side of 4 and the top side of 5. It can be concldued this triangle can be classified as scalene. then the correct choice is A. scalene

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mote1985 [20]

Answer:

b

Step-by-step explanation:

4 0
3 years ago
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If y=3x+1 were changed to y=x+1 how would the graph of the new function compare with the original?
Olegator [25]
F(x)=3x+1  (preimage)
g(x)=x+1  (image)
it is undergoing a reduction/compression with translation.
In general, a linear transformation is
g(x) = a*f(bx-h)+k
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Note that the y-intercept remains unchanged.
5 0
3 years ago
Farah rolls a fair dice and flips a fair coin. What is the probability of obtaining a 5 and a head? Give your answer in its simp
yan [13]

Answer:

1/12

Step-by-step explanation:

1 in 6 probablity on the dice and 1/2 probablity on the coin. multiply 6 and 2 = 12

1/12 probablity

i think this is the right answer but im not 100 percent sure

6 0
3 years ago
What is -3(2x-4)+9x-8
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Answer:

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Step-by-step explanation:

3 0
3 years ago
From a thin piece of cardboard 30 in. by 30 in., square corners are cut out so that the sides can be folded up to make a box. Wh
Brilliant_brown [7]

Answer:

Dimensions 5in x 10in x 10in will yeild a box with a max. volume of  500 cubic inches

Step-by-step explanation:

Volume =  height x length x width

considering 'x' as the length of the square corners that has been cut out from the cardboard and also, that is height of the cardboard box.

square corners are cut out so that the sides can be folded up to make a box, cardboard sides would reduce by 2x

therefore,

V = x  (30-2x) (30-2x) ---> eq(1)

V=( 30x - 2x²) (30-2x)

V= 900x- 60x² - 60x² + 4x³

V=  4x³ - 120 x²+ 900x

Taking derivative w.r.t 'x'

dV/dx = 12x² - 240 x +900

dV/dx = 4 (3x² - 60x +225)

For maximum dV/dx, make it equal zero

dV/dx = 0

so,  4 (3x² - 60x +225)=0

3x² - 60x+225=0   (taking 3 common)

x² - 20x + 75 =0

Solving this quadratic equation

x² - 15x -5x + 75 =0

x(x-15) - 5(x-15) =0

Either (x-15)=0

x=15

Or x-5=0

x = 5

if we substitute x=15 in eq(1), volume becomes zero.

therefore, x cannot be 15

When x= 5

eq(1)=>V = 5  (30-2(5)) (30-2(5))

V= 5 (10) (10)

V= 500 cubic inches,

Therefore, Dimensions 5in x 10in x 10in will yeild a box with a max. volume of  500 cubic inches

7 0
3 years ago
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