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Darya [45]
3 years ago
15

Find the slope and y-intercept from the following graph of a linear equation.

Mathematics
1 answer:
Murljashka [212]3 years ago
8 0

For this question, you need to find the slope-intercept form of the graph. To do this, start with two points and plug them into y2-y1 / x2-x1.

(-1,-1)(1,7)

7 - - 1 / 1 - - 1 = 8/2 = 4

Therfore, your slope is 4

Next, the y-intercept. This is the point where the graph crosses with the y. In this problem, the lines intercept at the point (0,3).

Therefore, your y-intercept is 3

Y-intercept = 3, Slope = 4

Slope-Intercept form is y = 4x + 3

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The sum of two numbers is 31.The product of the two numbers is 150. What are the two numbers?
Nikolay [14]
The two numbers I will call x and y.
x + y = 31
x * y = 150

You then solve for one variable in either equation and substitute it into the other equation.

x + y = 31
x = 31 - y

Then you plug it in:
x * y = 150
(31 - y) * y = 150
-y² + 31y = 150
y² - 31y + 150 = 0            Then factor:
(y - 6)(y - 25) = 0
y - 6 = 0        y - 25 = 0
y = 6             y = 25

When you plug y into the original equations, it comes out that the two numbers are 6 and 25. You can check your work because 6+25 = 31 and 6*25 = 150. Hope this helps! :)
5 0
3 years ago
14.31782106 rounded to the nearest foot
Leviafan [203]
I believe it is 14 ..
3 0
3 years ago
Please help me I don’t know the answer
lukranit [14]

Answer:

D

Step-by-step explanation:

the highest real number stops at 4, which means all the sets of real number are less than 4.

4 0
3 years ago
Xavier wants to distribute his baseball card collection evenly among his 8 younger brothers. What equation can be used to find c
defon
This would be D:).... C = the number of cards his brothers each get. 

4 0
3 years ago
Find product of
harkovskaia [24]

Answer:

8x⁶y⁵ - 12x⁴y⁷

Step-by-step explanation:

→ 4xy² × 2x² - 3y² × x³y³

→ 4x⁴y⁵ × 2x² - 3y²

→ 8x⁶y⁵ - 12x⁴y⁷

HOPE THIS HELPS YOU

Follw me = 10 thanks

Mark as brainliest = 10 thanks

1 thanks to me = 2 thanks

8 0
3 years ago
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