First figure out how many times 9 can go into 25 **do the highest amount of times it can go in-
<span><span>9x1=9 </span><span>9x2=18 </span><span>9x3=27 </span><span>9x4=<span>36
nine can go in 2 times because 3 times would be way to much
so you're mixed number would be 2
now to figure out you're numerator do 25-18=7
Now it would be 2 7/25
so you're mixed number,then the numerator,finally denomantor ALWAYS stays the same.
*IF YOU'RE NUMERATOR AND DENOMANTOR CAN BE REDUCED THEN REDUCE</span></span></span>
Ten times the sum of two and five tenths and thirteen and 5 tenths.
To solve for m means to get it alone on a side
so..


Answer:
Mark C.
Step-by-step explanation:
If there are 27 students in both classes, it's logicial to multiply both classes by two to get the total students.
Since the <em>S</em> stands for the students absent, that should come after the brackets.