Let s represent the length of any one side of the original square. The longer side of the resulting rectangle is s + 9 and the shorter side s - 2.
The area of this rectangle is (s+9)(s-2) = 60 in^2.
This is a quadratic equation and can be solved using various methods. Let's rewrite this equation in standard form: s^2 + 7s - 18 = 60, or:
s^2 + 7s - 78 = 0. This factors as follows: (s+13)(s-6)=0, so that s = -13 and s= 6. Discard s = -13, since the side length cannot be negative. Then s = 6, and the area of the original square was 36 in^2.
Answer:
Step-by-step explanation:
27.068
28.08
28.15
29.94
Answer:
y = -0.8x - 5
Step-by-step explanation:
x1 = (XA + XB) / 2 = -5
y1 = (YA + YB) / 2 = -1
m = (XA - XB) / (YA - YB) = -0
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(y - -1) = -0.8(x - -5)
y - -1 = -0.8x - 4
y = -0.8x - 4 + -1
y = -0.8x - 5
You go up 4 times and go to the left 2 times so the slope would be 4/-2
