A queue remember the order of its elements, but only adds at the tail and removes from the head.
<h3>What is a stack?</h3>
A stack can be defined as a collection that is designed and developed to remember the order of its elements, while allowing elements to be added and removed only at one end i.e either head or tail.
<h3>What is a
queue?</h3>
A queue can be defined as a collection that is designed and developed to remember the order of its elements, and it only allow elements to be added (inserted) at one end and removed only at the other end.
In this context, we can infer and logically deduce that, a queue remember the order of its elements, but would only add at the tail while removing from the head.
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Complete Question:
A remember the order of its elements, but only adds at the tail and removes from the head
As a driver that is approaching an about, it is very important to respect the drivers that are already in the about.
<h3>
What is an About?</h3>
An about is basically a junction that is circular in shape, in an about the vehicle at the left is given very high priority.
The driver of the SUV should wait for the oncoming vehicle to clear before he/she enter
Learn more about Round About here:
brainly.com/question/12811263
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The board of reviewers rejected carlos's research Paper on account of; Plagiarism
<h3>Implications of Plagiarism </h3>
Plagiarism is simply defined as the act of using another person's work or ideas as your own without their consent.
Now, we see that Carlos was doing a research and where he used information and data from Erik erikson but he failed to cite or credit him for such info and as such this is termed as plagiarism.
Read more about plagiarism at;brainly.com/question/14806635
Hello oddworld7836!
Factor the expression into an equivalent form 12y² - 75.
By observing the expression, we can see that, 3 is the only common factor in both the terms of the expression. So, take the common factor 3 out.
Now, look at (4y² - 25). They don't have any common factors but they appear in the form of the algebraic identity ⇨ a² - b² = (a + b) (a - b). Here,
- a² = 4, a = 2 (√a² = ✓4 = 2)
- b² = 25, b = 5 (√b² = ✓25 = 5)
So, the (4y² + 25) becomes...
Now, bring the 3 (common factor) & rewrite the complete expression.
We can't further simplify it. Also, remember that the simplified form of an expression is equivalent to the expression. So, 3 (2y - 5) (2y + 5) is equivalent to 12y² - 75.
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