Solve using gauss-Jordan elimination X1 - 3x2 = -5 -3x1 - x2 = 5
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<h3>Given:</h3><h3>Large cone:</h3>
- r= 8 cm
- h= 20 cm
- r= 4 cm
- h= 10cm
- r: radius
- h: height
- The volume of the frustum of the given cone.
- Frustum is a part of a cone formed by cutting off the top by a parallel plane.
Let's solve!
First, let's find the volume of the smaller cone.
Substitute the values according to the
formula.
Now, we can round off to the nearest hundredth.
The value in the thousandths place is smaller than 5 so we won't have to round up.
Next, let's find the volume of the bigger cone.
Substitute the values according to the formula.
Now, we can round off to the nearest hundredth.
The value in thousandths place is smaller than 5 so we won't have to round up.
Now, we can find the volume of the frustum.
We'll have to minus the volume of the smaller cone from the bigger cone.
<u>Hence, the volume of the frustum is 1172.86 cubic centimeters.</u>