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zaharov [31]
3 years ago
14

Which of the following statements is true according to the measurements in the diagram?

Mathematics
2 answers:
e-lub [12.9K]3 years ago
8 0

Let's look at the corresponding ratios:

\frac{AB}{ED}=\frac{24}{30}=\frac{4}{5}\\\frac{BC}{DC}=\frac{16}{20}=\frac{4}{5}\\\frac{AC}{EC}=\frac{21}{28}=\frac{3}{4}\\

And we see that the three aren't equal.

Hence, $\Delta ABC$ and $\Delta EDC$ are not similar.

IgorC [24]3 years ago
7 0

Answer:

°[Option 3] => Triangle ABC and Triangle EDC are not similar

Step-by-step explanation:

The angles nor the sides are congruent in this image.

Please mark Brainliest

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8cm

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The table shows the steps for solving the given inequality for x.
kenny6666 [7]

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8 0
3 years ago
Read 2 more answers
a boy is standing on a pole of height 14.7m throws a stone upwards. it moves in a vertical line slightly away from the pole and
fomenos

Answer:

The time taken for the upward motion is 1 second. The same time is taken for the downward motion

It reaches a maximum height of 4.9 meters.

Step-by-step explanation:

The equation of motion is:

x(t) = -4.9t^{2} + 9.8t

Since the term which multiplies t squared is negative, the graph is concave down, that is, x increases until the vertex, where it reaches it's maximum height, then it decreases.

Vertex of a quadratic equation:

Quadratic equation in the format x(t) = at^{2} + bt + c

The vertex is the point (t_{v}, x(t_{v})), in which

t_{v} = -\frac{b}{2a}

In this question:

x(t) = -4.9t^{2} + 9.8t

So a = -4.9, b = 9.8

Vertex:

t_{v} = -\frac{9.8}{2*(-4.9)} = 1

The time taken for the upward motion is 1 second.

x(t_{v}) = x(1) = 9.8*1 - 4.9*(1)^{2} = 4.9

It reaches a maximum height of 4.9 meters.

Downward motion:

From the vertex to the ground.

The ground is t when x = 0. So

-4.9t^{2} + 9.8t = 0

4.9t^{2} - 9.8t = 0

4.9t(t - 2) = 0

4.9t = 0

t = 0

Or

t - 2 = 0

t = 2

It reaches the ground when t = 2 seconds.

The downward motion started at the vertex, when t = 1.

So the duration of the downward motion is 2 - 1 = 1 second.

5 0
3 years ago
I have 90% after about 75%
kkurt [141]

The lowest grade he could earn is 120% of the grade at the end of the semester.

The following statement is given:

I have 90% after about 75% of the semester.

We are asked to find the lowest grade by the end of this semester.

<h3>What is Percentage?</h3>

A percentage is a number expressed as a fraction of 100.

- 50% = 50/100 = 1/2

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We can write this statement "I have a 90% grade after about 75% of the semester" as:

90% grade  =  75% semester.............(1)


By the end of the semester means at 100% semester.

Multiplying equation (1) by 100/ 75 on both sides of the equation.

We get,

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120% grade = 100%

Thus the lowest grade he could earn is 120% of the grade at the end of the semester.

Learn more about Percentages here:

brainly.com/question/24159063

#SPJ1

6 0
2 years ago
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