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Nimfa-mama [501]
3 years ago
8

The length of a rectangle is 72 cm and the diagonal measures 75 cm. Find the width and perimeter of the rectangle.

Mathematics
1 answer:
finlep [7]3 years ago
4 0
W <span>= </span><span>21 </span><span>cm</span>Hope that helped!
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Z is the midpoint of XY<br> XY = 27
Nimfa-mama [501]

X=13.5

Y=13.5

Therefore Z is 13.5

4 0
2 years ago
NO EXPLANATION NEEDED
Degger [83]
10/2 so 5 for 53, 10/4 so 5/2 or 2.5 for 54, and 10/3 or 3.333. For simplicity i divided everything by 10 to remove an extra zero but the answers would still be the same after you reduced
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3 years ago
Q= QUADRADO
Lubov Fominskaja [6]
Answer
C x Q x T = ? = 24
6 0
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Please let me know what you guys think about this problem
Molodets [167]

Answer:

8.8%

Step-by-step explanation:

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4 0
3 years ago
Find a linear second-order differential equation f(x, y, y', y'') = 0 for which y = c1x + c2x3 is a two-parameter family of solu
Alisiya [41]
Let y=C_1x+C_2x^3=C_1y_1+C_2y_2. Then y_1 and y_2 are two fundamental, linearly independent solution that satisfy

f(x,y_1,{y_1}',{y_1}'')=0
f(x,y_2,{y_2}',{y_2}'')=0

Note that {y_1}'=1, so that x{y_1}'-y_1=0. Adding y'' doesn't change this, since {y_1}''=0.

So if we suppose

f(x,y,y',y'')=y''+xy'-y=0

then substituting y=y_2 would give

6x+x(3x^2)-x^3=6x+2x^3\neq0

To make sure everything cancels out, multiply the second degree term by -\dfrac{x^2}3, so that

f(x,y,y',y'')=-\dfrac{x^2}3y''+xy'-y

Then if y=y_1+y_2, we get

-\dfrac{x^2}3(0+6x)+x(1+3x^2)-(x+x^3)=-2x^3+x+3x^3-x-x^3=0

as desired. So one possible ODE would be

-\dfrac{x^2}3y''+xy'-y=0\iff x^2y''-3xy'+3y=0

(See "Euler-Cauchy equation" for more info)
6 0
3 years ago
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