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3 years ago

The length of a rectangle is 72 cm and the diagonal measures 75 cm. Find the width and perimeter of the rectangle.

Mathematics

1 answer:

finlep [7]3 years ago

4 0

W = 21 cmHope that helped!

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Z is the midpoint of XY XY = 27

Nimfa-mama [501]

X=13.5

Y=13.5

Therefore Z is 13.5

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2 years ago

NO EXPLANATION NEEDED

Degger [83]

10/2 so 5 for 53, 10/4 so 5/2 or 2.5 for 54, and 10/3 or 3.333. For simplicity i divided everything by 10 to remove an extra zero but the answers would still be the same after you reduced

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3 years ago

Q= QUADRADO

Lubov Fominskaja [6]

Answer
C x Q x T = ? = 24

6 0

3 years ago

Please let me know what you guys think about this problem

Molodets [167]

Answer:

8.8%

Step-by-step explanation:

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3 years ago

Find a linear second-order differential equation f(x, y, y', y'') = 0 for which y = c1x + c2x3 is a two-parameter family of solu

Alisiya [41]

Let $y=C_1x+C_2x^3=C_1y_1+C_2y_2$ . Then $y_1$ and $y_2$ are two fundamental, linearly independent solution that satisfy

$f(x,y_1,{y_1}',{y_1}'')=0$
$f(x,y_2,{y_2}',{y_2}'')=0$

Note that ${y_1}'=1$ , so that $x{y_1}'-y_1=0$ . Adding $y''$ doesn't change this, since ${y_1}''=0$ .

So if we suppose

$f(x,y,y',y'')=y''+xy'-y=0$

then substituting $y=y_2$ would give

$6x+x(3x^2)-x^3=6x+2x^3\neq0$

To make sure everything cancels out, multiply the second degree term by $-\dfrac{x^2}3$ , so that

$f(x,y,y',y'')=-\dfrac{x^2}3y''+xy'-y$

Then if $y=y_1+y_2$ , we get

$-\dfrac{x^2}3(0+6x)+x(1+3x^2)-(x+x^3)=-2x^3+x+3x^3-x-x^3=0$

as desired. So one possible ODE would be

$-\dfrac{x^2}3y''+xy'-y=0\iff x^2y''-3xy'+3y=0$

(See "Euler-Cauchy equation" for more info)

6 0

3 years ago