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julia-pushkina [17]

2 years ago

6

WHAT IS

ign="absmiddle" class="latex-formula"> IN QUADRATICS, TONS OF POINTS GIVEN

1 answer:

kirill115 [55]2 years ago

5 0

Its the quadratic formula

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if your watch loses 5 minutes each hour and you set the time correctly at 7.00, what is the actual time when your watch shows la

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The correct answer would be 10am (if by 7 you mean 7am)

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Nadusha1986 [10]

(x-4)² + (x-2)² = x²

(x² - 8x + 16 ) + (x² - 4x + 4) = x

2x² -12x + 20 = x

2x²-12x + 20 - x = 0

2x² - 13x + 20 = 0

(2x-5) (x-4) = 0

2x-5 = 0

2x = 5

x = ⁵/₂

x-4 = 0

x = 4

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2 years ago

part 3. Find the value of the trig function indicated, use Pythagorean theorem to find the third side if you need it.

Nat2105 [25]

Answer: $\bold{9)\ \sin \theta=\dfrac{1}{3}\qquad 10)\ \sin \theta = \dfrac{4}{5}\qquad 11)\ \cos \theta = \dfrac{\sqrt{11}}{6}\qquad 12)\ \tan \theta = \dfrac{17\sqrt2}{26}}$

<u>Step-by-step explanation:</u>

Pythagorean Theorem is: a² + b² = c² , <em>where "c" is the hypotenuse</em>

<em />

$9)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{4}{12}\quad \rightarrow \large\boxed{\dfrac{1}{3}}$

Note: 4² + (8√2)² = hypotenuse² → hypotenuse = 12

$10)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{16}{20}\quad \rightarrow \large\boxed{\dfrac{4}{5}}$

Note: 12² + opposite² = 20² → opposite = 16

$11)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{\sqrt{11}}{6}\quad =\large\boxed{\dfrac{\sqrt{11}}{6}}$

Note: adjacent² + 5² = 6² → adjacent = √11

$12)\ \tan \theta=\dfrac{\text{side opposite of}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{17}{13\sqrt2}\quad =\large\boxed{\dfrac{17\sqrt2}{26}}$

Note: adjacent² + 7² = (13√2)² → adjacent = 17

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3 years ago

124 ounces decreased by 67%

slavikrds [6]

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