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2 years ago

Which of the following cosine functions has a period of 3π?

Mathematics

1 answer:

skelet666 [1.2K]2 years ago

7 0

Answer:

y = cos 2/3 x

Step-by-step explanation:

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3 years ago

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3 years ago

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How do i solve this?

shusha [124]

Answer:

Step-by-step explanation:

You can use Pythagoras Theorem,

$8^{2} + y^{2} = (8\sqrt{6} )^{2} \\ y^{2} = (8\sqrt{6} )^{2} - 8^{2} \\y^{2} = 384 - 64\\y^{2} = 320\\y = \sqrt{320}$

∴ $y = 8\sqrt{5}$

Hope that helps!!

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3 years ago

Se the distributive property to remove the parentheses. -(-3v-4w+1)

KIM [24]

Hii!

$\leadsto\parallel\boldsymbol{Answer.}\parallel\gets$

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3v+4w-1

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$\leadsto\parallel\boldsymbol{Explanation.}\parallel\gets$

We use the distributive property to "distribute" the minus sign.

$\sf -(-3v-4w+1)=-1\cdot(-3v)+(-1)\cdot(-4w)+(-1)\cdot1}$ .

Simplify!

$\sf 3v+4w-1}$ . Which is our final answer.

Hope that this helped! Best wishes.

$\textsl{Reach far. Aim high. Dream big.}$

$\boldsymbol{-Greetings!-}$

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2 years ago