Answer:
$1.46
Step-by-step explanation:
2t > 324
divide each side by 2
2t/2 > 324/2
t > 162
12y >= 1
divide each side by 12
12y/22 >= 1/12
y >= 1/12
x/9.5 < 11
multiple each side by 9.5
x/9.5 * 9.5 < 11 * 9.5
x < 105.5
BA&D's plan is better for those who use less data. The intersection point of the two plans is (2, 18), which means that both plans cost $18 when you use 2G of data. Anything using more data than that is less expensive with BA&D's plan.
To find the intersection point,
6+6g=10+4g
We cannot have a variable on both sides, so we will subtract 4g from both sides:
6+6g-4g=10+4g-4g
6+2g=10
Subtract 6 from both sides:
6+2g-6=10-6
2g=4
Divide both sides by 2:
2g/2 = 4/2
g = 2
This is the point where the plans cost the same. If we try a number smaller than 2 in both plans,
6+6(1) = 6+6 = 12
10+4(1) = 10+4 = 14
BA&D's plan is less.
Answer:
$11,500 was invested at 13%.
$17,500 was invested at 4%
Step-by-step explanation:
This is a simple interest problem.
The simple interest formula is given by:

In which E is the amount of interest earned, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time.
After t years, the total amount of money is:

In this question:
Loans totaling 29,000.
P was invested at 13%
29000 - P was invested at 4%.
First investment:
Principal P.
Interest 13% = 0.13.
One year, so t = 1.
So


Second investment:
Principal 29000 - P.
Interest 4% = 0.04.
One year, so t = 1.
So

The total interest earned for both loans was $2,195.00.
This means that 
So

So we solve the following system:







$11,500 was invested at 13%.
29000 - 11500 = 17500
$17,500 was invested at 4%