1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Oksana_A [137]
3 years ago
6

The velocity on sound in air is _________m/s.

Physics
2 answers:
tensa zangetsu [6.8K]3 years ago
8 0

The velocity on sound in air is 330 m/s.

kotykmax [81]3 years ago
7 0
330 m/s would be the correct answer to fill in the blank
You might be interested in
What two pieces of information are needed to determine the diameter of a faraway object?
xxTIMURxx [149]
Distance and angular size
4 0
4 years ago
The density of the gold is 19.3g/cm3.
elena55 [62]

If both nuggets have the same mass and different densities then it can be concluded that the volume with the highest density is smaller.

For, so to speak, density is a relation of how much mass is there in a given volume. So the more the mass and the smaller the volume, the greater the density.

To verify this, let us calculate the volumes of iron pyrite and gold pyrite.

For the iron pyrite nugget:

density = mass / volume

volume = mass / density

volume = 50/5

volume = 10cm3


For the gold nugget:

volume = mass / density

volume = 50 / 19.3

volume = 2.59cm3


Therefore it is found that the nugget with the highest density (gold) is the one with the lowest volume.

3 0
3 years ago
The vectors of the magnetic field around a long, straight, current-carrying wire are:
pochemuha

Answer:

concentric with the wire

Explanation:

the magnetic field around a long straight, current carrying wire form concentric circles around the wire.

7 0
3 years ago
How does the vertical acceleration at point a compare to the vertical acceleration at point c?
Anika [276]
The vertical accelerations of the point a and point c are equal. because the vertical acceleration is due to the acceleration due to gravity. Acceleration due to gravity<span> may refer to: Gravitational acceleration, the acceleration caused by the gravitational attraction of massive bodies in general, which is equal to 9.8 m/s^2</span>
4 0
3 years ago
Read 2 more answers
a disk with a radius of 0.1 m is spinning about its center with a constant angular speed of 10 rad/sec. What are the speed and m
padilas [110]

The speed of the bug at the rim of the circular disk is \boxed{1\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {\text{s}}}} \right.\kern-\nulldelimiterspace} {\text{s}}}} and the acceleration of the bug is \boxed{10\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {{{\text{s}}^{\text{2}}}}}} \right.\kern-\nulldelimiterspace} {{{\text{s}}^{\text{2}}}}}}.

Further Explanation:

Given:

The angular velocity of the disk is 10\,{{{\text{rad}}} \mathord{\left/{\vphantom {{{\text{rad}}} {\text{s}}}} \right.\kern-\nulldelimiterspace} {\text{s}}}.

The radius of the circular disk is 0.1\,{\text{m}}.

Concept:

The linear speed of the bug present at the rim of the circular disk is given by.

v = r \times \omega  

Here, v is the linear speed,r is the radius of the disk and \omega is the angular speed of the disk.

Substitute 0.1\,{\text{m}} for r and 10\,{{{\text{rad}}} \mathord{\left/{\vphantom {{{\text{rad}}} {\text{s}}}} \right.\kern-\nulldelimiterspace} {\text{s}}} for \omega in above expression.

\begin{aligned}v &= 0.1\,{\text{m}} \times 10\,{{{\text{rad}}} \mathord{\left/{\vphantom {{{\text{rad}}} {\text{s}}}} \right. \kern-\nulldelimiterspace} {\text{s}}} \\&= 1\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {\text{s}}}} \right.\kern-\nulldelimiterspace} {\text{s}}} \\\end{aligned}  

The magnitude of the centripetal acceleration of the bug cling to the rim of the disk is given as.

{a_c} = \dfrac{{{v^2}}}{r}  

Substitute 1\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {\text{s}}}} \right.\kern-\nulldelimiterspace} {\text{s}}} for v and 0.1\,{\text{m}} for r in above equation.

\begin{aligned}a_c&=\dfrac{(1\text{m/s})^2}{0.1\text{m}}\\&=\frac{1}{0.1}\text{m/s}^2\\&=10\,\text{m/s}^2\end{aligned}  

Thus, the speed of the bug at the rim of the circular disk is \boxed{1\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {\text{s}}}} \right.\kern-\nulldelimiterspace} {\text{s}}}} and the acceleration of the bug is \boxed{10\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {{{\text{s}}^{\text{2}}}}}} \right.\kern-\nulldelimiterspace} {{{\text{s}}^{\text{2}}}}}}.

Learn More:

  1. For typical rubber-on-concrete friction, what is the shortest time in which a car could accelerate from 0 to 80 mph brainly.com/question/7174363
  2. Max and Maya are riding on a merry-go-round that rotates at a constant speed. If the merry-go-round makes 3.5 revolutions in 9.2 seconds brainly.com/question/8444623
  3. Which of the following are units for expressing rotational velocity, commonly denoted by ω brainly.com/question/2887706

Answer Details:

Grade: College

Chapter: Uniform Circular motion

Subject: Physics

Keywords:  Circular disk, circular motion, angular speed, linear speed, bug clinging, rim of the disk, acceleration, magnitude, constant, rad/s.

7 0
3 years ago
Read 2 more answers
Other questions:
  • When waves strike an object and bounce off, what has occured
    8·1 answer
  • Match the boundary with its characteristic
    14·2 answers
  • Which of the following best describes the role of attention from a caregiver on the development of intelligence?
    15·2 answers
  • How images from space of earth and other objects are useful
    15·1 answer
  • Air is forced through the water to remove gases is called?
    15·2 answers
  • How much water can moss hold PLEASE HELP
    14·1 answer
  • Which of the following include exact numbers? a) The speed of light in a vacuum is a physical constant; to the nearest m/s, it i
    5·1 answer
  • What are the contrast of adaptation vs natural selection?
    7·1 answer
  • Help ppl ..I don’t know nothing
    6·1 answer
  • What is photons as in physics ​
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!