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3 years ago

What two pieces of information are needed to determine the diameter of a faraway object?

Physics

1 answer:

xxTIMURxx [149]3 years ago

4 0

Distance and angular size

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The sediment deposited by glaciers is called __________ .

nalin [4]

Answer:

The sediment deposited by glaciers is called Glacial deposition.

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3 years ago

Two identical point charges in outer space are held apart at a distance D. As soon as the charges are released, each begins movi

Karo-lina-s [1.5K]

The new acceleration is B) 4a

Explanation:

According to Newton's second law, the acceleration of an object is proportional to the force exerted on it:

$a=\frac{F}{m}$

where

F is the net force on the object

m is its mass

a is the acceleration

This means that we can analyze the problem in terms of the force involved. The electric force between the charges at the beginning is given by

$F=k\frac{q_1 q_2}{D^2}$

where:

$k=8.99\cdot 10^9 Nm^{-2}C^{-2}$ is the Coulomb's constant

$q_1, q_2$ are the two charges

D is the separation between the two charges

Later, the charges are separated by a new distance

D' = D/2

Therefore, the new force between them is

$F'=k\frac{q_1 q_2}{(D/2)^2}=4(k\frac{q_1 q_2}{D^2})=4F$

So, the force has increased by a factor of 4: and since the acceleration is proportional to the force, this means that the acceleration has also increased by a factor of 4, so the correct choice is

B) 4a

Learn more about forces and acceleration:

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#LearnwithBrainly

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3 years ago

A car is traveling at 7.1m/s accelerates 4.3 m/s^2 to reach a speed of 16.0 m/s how long does it take for this acceleration to o

Bond [772]

<u>Answer</u>

2.06977 seconds

<u>Explanation</u>

Acceleration, a, is the rate of change of velocity

a = (v-u)/t

where v and u are final and initial velocities respectively.

4.3 = (16.0 - 7.1)/t

4.3 = 8.9/t

t = 8.9/4.3

= 2.06977 seconds

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3 years ago

High-energy particles are observed in laboratories by photographing the tracks they leave in certain detectors; the length of th

murzikaleks [220]

Answer:

Lifetime = 4.928 x 10^-32 s

Explanation:

(1 / v2 – 1 / c2) x2 = T2

T2 = (1/ 297900000 – 1 / 90000000000000000) 0.0000013225

T2 = (3.357 x 10^-9 x 1.11 x 10^-17) 1.3225 x 10^-6

T2 = (3.726 x 10^-26) 1.3225 x 10^-6 = 4.928 x 10^-32 s

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3 years ago

A CG amplifier using an NMOS transistor for which gm = 2 mA/V has a 5-k drain resistance RD and a 5-k load resistance RL. The am

arlik [135]

Answer: Input Resistance (Rin) = 500 ohms , overall voltage Gain (GV) = 2 volts / volts , ID = 4/9 = 0.44 A

Explanation:

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3 years ago