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Hunter-Best [27]
4 years ago
10

What two pieces of information are needed to determine the diameter of a faraway object?

Physics
1 answer:
xxTIMURxx [149]4 years ago
4 0
Distance and angular size
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A CD-ROM is a compact disk that
Greeley [361]
<span>CD stands for Compact Disk and ROM stands for Read Only Memory. CD-ROMS were designed to store information that the computers can read and you cannot overwirte on it. S,o the answer is the option C.: A CD-ROM is a compact disk that contains stored information that can be read on a computer.</span>
6 0
3 years ago
A pressure vessel that has a volume of 10m3 is used to store high-pressure air for operating a supersonic wind tunnel. If the ai
Anna71 [15]

Answer:

The mass of air stored in the vessel is 235.34 kilograms.

Explanation:

Let supossed that air inside pressure vessel is an ideal gas, The density of the air (\rho), measured in kilograms per cubic meter, is defined by following equation:

\rho = \frac{P\cdot M}{R_{u}\cdot T} (1)

Where:

P - Pressure, measured in kilopascals.

M - Molar mass, measured in kilomoles per kilogram.

R_{u} - Ideal gas constant, measured in kilopascal-cubic meters per kilomole-Kelvin.

T - Temperature, measured in Kelvin.

If we know that P = 2026.5\,kPa, M = 28.965\,\frac{kg}{kmol}, R_{u} = 8.314\,\frac{kPa\cdot m^{2}}{kmol\cdot K} and T = 300\,K, then the density of air is:

\rho = \frac{(2026.5\,kPa)\cdot \left(28.965\,\frac{kg}{kmol} \right)}{\left(8.314\,\frac{kPa\cdot m^{2}}{kmol\cdot K} \right)\cdot (300\,K)}

\rho = 23.534\,\frac{kg}{m^{3}}

The mass of air stored in the vessel is derived from definition of density. That is:

m = \rho \cdot V (2)

Where m is the mass, measured in kilograms.

If we know that \rho = 23.534\,\frac{kg}{m^{3}} and V = 10\,m^{3}, then the mass of air stored in the vessel is:

m = \left(23.534\,\frac{kg}{m^{3}} \right)\cdot (10\,m^{3})

m = 235.34\,kg

The mass of air stored in the vessel is 235.34 kilograms.

7 0
3 years ago
PLEASE HELP ILL GIVE CROWN!!!!
Mkey [24]

Answer:

A)

Explanation:

The lowest latitudes get the most energy from the sun. The highest latitudes get the least.

3 0
3 years ago
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The radius RH of a black hole, also known as the event horizon, marks the location where not even light itself can escape from t
olga nikolaevna [1]

Solution:

a) We know acceleration due to gravity, g = GM/r²

Differential change, dg/dr = -2GM/r³

Here, r = 50*Rh = 50*2GM/c² = 100GM/c ²

My height, h=dr = 1.7 m

Difference in gravitational acceleration between my head and my feet, dg = -10 m/s²

or,   dg/dr = -10/1.7 = -2GM/(100GM/c²)³

or,     5.9*100³*G²*M² = 2c⁶

or,   M = 0.59*c³/(1000G) = 2.39*1032 kg = [(2.39*1032)/(1.99*1030 )]Ms = 120*Ms

Mass of black hole which we can tolerate at the given distance is 120 time the mass of Sun.

b) This limit an upper limit ,we can tolerate smaller masses only.

4 0
3 years ago
An object with a mass of 2.0 kg accelerates 2.0 m/s 2when an unknown force is applied to it. What is the amount of force?
Musya8 [376]

Answer:

4 N

Explanation:

mass = 2 kg

acceleration = 2 m/s^2

Force = mass * acceleration

         = 2 *2

         = 4 N

5 0
3 years ago
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