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Vlada [557]
3 years ago
14

Match the boundary with its characteristic

Physics
2 answers:
kondor19780726 [428]3 years ago
7 0
<span>Matching the boundary with its characteristics 1. Convergent - C. Compression 2. Divergent - B. Along ocean ridges 3. Transform - A. Along strike-slip faults The compression that occur in the convergent boundary causes the reverse fault in the earth crust. So in the divergent boundary two crust plates move apart causing a normal fault along the ocean ridges. The faults in the transform boundary happens at the place where plates slide laterally.</span>
Anarel [89]3 years ago
4 0
The  answers are the following:
1. Convergent - C. Compression
2. Divergent - B. Along ocean ridges
3. Transform - A. Along strike-slip faults

These are the plate tectonic boundaries that which causes earthquakes when they move. Each tectonic boundaries result to different movement of the plates and forms new landmasses.

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A rock is dropped from a vertical cliff. The rock takes 6.00 s to reach the ground below the cliff. What is the height of the cl
Lana71 [14]

Answer:

180 m

Explanation:

The rock follows a free-fall motion - so the vertical distance covered can be found by using the equation

h=\frac{1}{2}gt^2

where

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t = 6.00 s is the time of the fall

Substituting these data, we find the height of the cliff:

h=\frac{1}{2}(10 m/s^2)(6.00 s)^2=180 m

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3 years ago
Explain why 15yr old need more calcium than adults
Tom [10]

Answer:

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3 years ago
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An automobile with a tangential speed of 54.1 km/h follows a circular road that has a radius of 41.6 m. The automobile has a mas
Viefleur [7K]

1) Available force of friction: 6174 N

2) No

Explanation:

1)

The magnitude of the frictional force between the car's tires and the pavement of the road is given by

F_f=\mu mg

where

\mu is the coefficient of friction

m is the mass of the car

g is the acceleration of gravity

For the car in this problem, we have:

\mu=0.500 (coefficient of friction)

m = 1260 kg (mass of the car)

g=9.8 m/s^2

Therefore, the force of friction is

F_f=(0.500)(1260)(9.8)=6174 N

2)

In order to mantain the car in circular motion, the force of friction must be at least equal to the centripetal force.

The centripetal force is given by

F=m\frac{v^2}{r}

where

m is the mass of the car

v is the tangential speed

r is the radius of the curve

In this problem, we have

m = 1260 kg

v=54.1 km/h =15.0 m/s is the tangential speed

r = 41.6 m is the radius of the curve

Therefore, the centripetal force is

F=(1260)\frac{15.0^2}{41.6}=6814 N

Therefore, the force of friction is not enough to keep the car in the curve, since F_f

4 0
3 years ago
Many cultures experience music with their whole:
coldgirl [10]

Answer:

entertaining form of repetition

Explanation:

=>

7 0
2 years ago
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AleksandrR [38]
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