The width of the insect is 0.17 cm and the height of the insect is 0.125 cm.
Step-by-step explanation:
Step 1:
The scale factor is given by dividing the measurement after scaling by the same measurement
The given drawing of the insect is larger than the actual insect.
The scale factor is 20: 1 which means 20 cm on the drawing is 1 cm on the actual insect.
Step 2:
To obtain the actual insect's dimensions, we divide the dimensions of the drawing by 20.
The width of the actual insect 
The height of the actual insect 
The width of the insect is 0.17 cm and the height of the insect is 0.125 cm.
Answer:
Step-by-step explanation:
The missing image is attached below.
From the given information
The number of players is 44.
From the box plot;
The minimum weight = 154 pounds
The first quartile Q₁ = 159 which is 25% of the data below 159 pounds.
The second quartile Q₂ = 213 which is 50% of the data below 213 pounds
The third quartile Q₃ = 253 which is 75% of the data below 253 pounds
The maximum weight = 268 pounds.
Here, the value of 213 is the middle value and which signifies the median.
The 50% of the data are located both on the left side and the right side of the median.
Thus, the percentage of players weighting greater than or equal to 213 pounds is 50%.
Answer:
Therefore the required Equation of Circle
Step-by-step explanation:
Given:
End point of Diameter be
point A( x₁ , y₁) ≡ ( -2 ,-2 )
point B( x₂ , y₂) ≡ ( 4 , -10 )
To Find:
Equation of a circle =?
Solution:
When end points of the Diameter are A( x₁ , y₁) , B( x₂ , y₂). then the Equation of Circle is given as
Substituting the end point are
Applying Distributive Property we get
Therefore the required Equation of Circle
Answer:
I think C the fourth graph
Step-by-step explanation:
Answer:
rupee 300 will be the correct answer
