You have two 30-60-90 triangles, ADC and BDC.
The ratio of the lengths of the sides of a 30-60-90 triangle is
short leg : long leg : hypotenuse
1 : sqrt(3) : 2
Using triangle ADC, we can find length AC.
Using triangle BDC, we can find length BC.
Then AB = AC - BC
First, we find length AC.
Look at triangle ACD.
DC is the short leg opposite the 30-deg angle.
DC = 10sqrt(3)
AC = sqrt(3) * 10sqrt(3) = 3 * 10 = 30
Now, we find length BC.
Look at triangle BCD.
For triangle BCD, the long leg is DC and the short leg is BC.
BC = 10sqrt(3)/sqrt(3) = 10
AB = AC - BC = 30 - 10 = 20
Addition bc. you need adding to both sides x and will get this result of 3x+2 = 11
hope helped
Answer:
B
Step-by-step explanation:
Answer: Infinite Solutions
Elimination Method
-x + 3y - 9 = 0
x - 3y = -9
———————— x and y cancels out
-9 = -9; is True so infinite Solutions
Note: if the variables cancel out, and the statement is true, its infinite solutions
if the variable cancels out, and the statement is false, its no solutions
