Andrea has 3 tiles.

Mathematics

1 answer:

mash [69]3 years ago

4 0

Step-by-step explanation:

We are going to start by working out the interior angles so first of all to work out the interior angle we used the formula: num of sides - 2 * 180 for the sum of degrees in a shape.

Lets test this formula.

Lets say we have a square it has 4 sides 4-2 = 2 *180 = 360 this is correct,meaning we can trust this formula.

Now lets put it to use.

Octagon has 8 sides - 2 = 6.

6 * 180 = 1080

Pentagon has 5 sides - 2 = 3

3 * 180 = 540

Another Pentagon 5 sides - 2 = 3

3 * 180 = 540

We have to find out a single angle because it is one side that joins to the other, also if it is a perfect fit then all the single angles must add up to 360.

1080/8 sides = 135 degrees

540 / 5 sides = 108 degrees

We add these up,

135 + 108 + 108 = 351 which cannot be a possible fit because we need 360 degrees.

Hope this helps

You might be interested in

If h(x) = x – 7 and g(x) = x2, which expression is equivalent to (5 – 7)2 (5)2 – 7 (5)2(5 – 7) (5 – 7)x2

rodikova [14]

E are given with two functions: h(x) = x – 7 and g(x) = x2. In this problem, we are asked to determine the value of g(h(5)). first we get g(h(x)) which is equal to (x-7)2, when x is substituted by 5, then g(h(5)) = (5-7)^2 equal to 4

3 0

3 years ago

Simplify completely:

tigry1 [53]

Exponental law

$( \sqrt{x}) times ( \sqrt{n} )= \sqrt{xn}$ so
√(81y^5)=√81 times √(y^5)
√81=9 or -9
√(y^5)=y^2 times√y
answer is 9y^2 times √y or -9y^2 times √y

4 0

3 years ago

¿Cuál es el valor de la razón de cambio cuando tenemos un vaso con agua a temperatura ambiente al congelador por 15 minutos?

grandymaker [24]

Answer: $2 \°C/min$

Step-by-step explanation:

The rate of change is a measure in which one variable is modified in relation to another. In this case we have the variables:

Temperature in $\°C$

Time in $min$

Now, to calculate the rate of change, we have to divide one variable by the other. In this case the change in temperature $\Delta T$ divided by the time variation $\Delta t$ .