Ask question

Ask question

All categories

3 years ago

12

Find the value of x for which m || n

2 answers:

padilas [110]3 years ago

3 0

X=41 mlln (3x-18) / 99 and 105 percent with n on top left with x being unsolved but 31 is not relevant and 39 can’t make any sense given our formula and 33 can’t be the answer because it would be most likely 34 or 41 and they have 41 up there so it’s obviously the best choice.

JulijaS [17]3 years ago

3 0

Answer iCorrect answer is A.

You might be interested in

Simplify -5-√-44<br><br> i have no idea

Tatiana [17]

Answer:

Undefined

Step-by-step explanation:

The square root of a negative number does not exist in the set of real numbers so it would be Undefined

6 0

3 years ago

A stem and leaf plot titled High Temperatures in degrees Fahrenheit. The stems are 4, 5, 6, 7. The first column of leaves are 9,

ad-work [718]

Answer:

The temperature with the highest frequency is 54

Step-by-step explanation:

Given

The above data

Required

The temperature with the highest frequency

The first step, is to plot the stem and leaf plot.

$\begin{array}{cc}{4} & {9\ \ } & {5} & {2\ 4\ 4\ 6\ 8} & {6} & {0\ 1\ } & {7} & {2\ 3\ } \ \end{array}$

Next, is to identify the leaf with the highest frequency.

The leaf is 4 (with frequency 2)

Next, is to identify the accompanying stem of the leaf

The stem is 5

<em>Hence, the temperature with the highest frequency is 54</em>

5 0

3 years ago

Read 2 more answers

Part 2: NO LINKS!! NOT MULTIPLE CHOICE! Please help me

Dmitry_Shevchenko [17]

Answer:

(see attachment for tree diagram)

$\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}$

<h3><u>Part (a)</u></h3>

$\textsf{P(Head) and P(3)}=\sf \dfrac{1}{2} \times \dfrac{1}{6}=\dfrac{1}{12}$

<h3><u>Part (b)</u></h3>

$\textsf{P(Tail) and P(even)}=\sf \dfrac{1}{2} \times \dfrac{3}{6}=\dfrac{3}{12}=\dfrac{1}{4}$

<h3><u>Part (c)</u></h3>

$\textsf{P(not 6)}=\sf 1-\textsf{P(6)}=1-\dfrac{1}{6}=\dfrac{5}{6}$

$\implies \textsf{P(Head) and P(not 6)}=\sf \dfrac{1}{2} \times \dfrac{5}{6}=\dfrac{5}{12}$

<h3><u>Part (d)</u></h3>

As the six-sided die does not have a side labelled "7", the probability of rolling a 7 is zero.

$\implies \textsf{P(Head) and P(7)}=\sf \dfrac{1}{2} \times 0=0$

7 0

2 years ago

For which of the following equations is (-2, -3) not a solution?

bonufazy [111]

The second one -3x=4y-6

6 0

3 years ago

Which set of algebra tiles represents the sentence below? Carlton earned 3 more stamps. 1 box contains x and 3 boxes contain plu

Lapatulllka [165]

Answer:

The answer is A.

Step-by-step explanation:

Made a 100 on the quiz on E2020

4 0

3 years ago

Read 2 more answers