9514 1404 393
Answer:
x can be any value (infinite number of solutions)
Step-by-step explanation:
The equation simplifies to ...
2(x -2) +3 = 2x -1
2x -4 +3 = 2x -1
2x -1 = 2x -1
This is true for every value of x. There are an infinite number of solutions.
Answer:
The question is invalid. Please rewrite the question.
The polynomial p(x)=x^3-6x^2+32p(x)=x 3 −6x 2 +32p, left parenthesis, x, right parenthesis, equals, x, cubed, minus, 6, x, squar
STatiana [176]
Answer:
<h3>The remainder is zero</h3>
Step-by-step explanation:
Given the polynomial function p(x)=x^3-6x^2+32, if x-4 is a factor, then <u>we can find the remainder if the polynomial is divided by x -4.</u>
First we need to equate the function x - 4 to zero and find x;
x - 4 = 0
x= 0+4
x = 4
Next is to substitute x = 4 into the expression p(x)=x^3-6x^2+32
p(x)=x^3-6x^2+32
p(4)=(4)^3-6(4)^2+32
p(4) = 64 - 96 + 32
p(4) = 0
Hence the remainder when x-4 is divided by the polynomial is zero
Answer:
A. There are not 15 successes and 15 failures. A confidence interval can be computed by adding 2 successes and 2 failures.
Answer: 69.3 i hope that helps :)
Step-by-step explanation: