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3 years ago

If the ramp will be 3 feet above the ground and have a 4 foot Base , How long will the ramp be?

Mathematics

2 answers:

FinnZ [79.3K]3 years ago

6 0

Answer:

5 feet long

Step-by-step explanation:

According to the Pythagorean Theorem, a^2 + b^2 = c^2 where "a" and "b" are the two legs of the right triangle and "c" is the hypotenuse.

We are trying to find the part that is at an angle, which is "c". So if we know "a" is "3 and "b" is 4, we can plug the values into the equation.

3^2 + 4^2 = c^2 plug in the values

9 + 16 = c^2 simply the two squared values

25 = c^2 add the two values

5 = c take the square root of both sides

c = 5 switch the values

GalinKa [24]3 years ago

5 0

Answer:

Step-by-step explanation:

3^+4^=c^

9+16=c^

25=C^

5=c

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The prime factors of a number are 2, 2, 2, and 5. What is the number?

fgiga [73]

Answer: 40

Step-by-step explanation:

Since 40 could be = 1 x 40, 2 x 20, 4 x 10, or 5 x 8.

The Factors of 40 will therefore be: 1, 2, 4, 5, 8, 10, 20, 40.

The Prime factor then is: 2, 2, 2, 5

Multiplying them together gives 40.

7 0

2 years ago

If a number is divisible by 2, then the number ends with a 2. which of the following best describes a counter example to the con

Thepotemich [5.8K]

Answer: 44
Explanation: it is divisible by two but does not end with two

6 0

2 years ago

The improper fraction of 5 7/8

Licemer1 [7]

Its 47/8 hope this helped all you need to do is keep the 8 like how it is and then you do 5 times 8 and add 7 thats it

3 0

3 years ago

Read 2 more answers

Please someone answer this please

gladu [14]

Option C:

$\frac{3 a^{2} b^{11}}{2 }$ is equivalent to the given expression.

Solution:

Given expression:

$$\frac{-18 a^{-2} b^{5}}{-12 a^{-4} b^{-6}}$

To find which expression is equivalent to the given expression.

$$\frac{-18 a^{-2} b^{5}}{-12 a^{-4} b^{-6}}$

Using exponent rule: $\frac{1}{a^m}=a^{-m}, \ \ \frac{1}{a^{-m}}=a^{m}$

$$=\frac{-18 a^{-2} b^{5}a^{4} b^{6}}{-12 }$

$$=\frac{-18 a^{-2} a^{4} b^{5} b^{6}}{-12 }$

Using exponent rule: ${a^m}\cdot{a^n}=a^{m+n}$

$$=\frac{-18 a^{(-2+4)} b^{(5+6)}}{-12 }$

$$=\frac{-18 a^{2} b^{11}}{-12 }$

Divide both numerator and denominator by the common factor –6.

$$=\frac{3 a^{2} b^{11}}{2 }$

$$\frac{-18 a^{-2} b^{5}}{-12 a^{-4} b^{-6}}=\frac{3 a^{2} b^{11}}{2 }$

Therefore, $\frac{3 a^{2} b^{11}}{2 }$ is equivalent to the given expression.

Hence Option C is the correct answer.

8 0

3 years ago

Suppose that administrators of a large school district wish to estimate the proportion of children in the district enrolling in

11Alexandr11 [23.1K]

Answer:

95% z-confidence interval for the proportion of all children enrolled in kindergarten who attended preschool is between a lower limit of 0.528 and an upper limit of 0.772.

Step-by-step explanation:

Confidence interval = p + or - zsqrt[p(1-p) ÷ n]

p is sample proportion = 39/60 = 0.65

n is the number of children sampled = 60

Confidence level (C) = 95% = 0.95

Significance level = 1 - C = 1 - 0.95 = 0.05

Divide significance level by 2 to obtain critical value (z)

0.05/2 = 0.025 = 2.5%

z at 2.5% significance level = 1.96

zsqrt[p(1-p) ÷ n] = 1.96sqrt[0.65(1-0.65) ÷ 60] = 1.96sqrt[0.2275 ÷ 60] = 1.96sqrt(3.792×10^-3) = 1.96×0.062 = 0.122

Lower limit = p - 0.122 = 0.65 - 0.122 = 0.528

Upper limit = p + 0.122 = 0.65 + 0.122 = 0.772

95% confidence interval is between 0.528 and 0.772

5 0

2 years ago