Question

What are the solutions to the equation 4x^3 =36x

Answer 1

Answer:

The answer to your question is:

 x₁ = 0

x₂ = -3

x₃ = 3

Step-by-step explanation:

Equation   4x³ = 36 x

Process

                   4x³ - 36x = 0

                  4x (x² - 9) = 0

                   4x (x + 3)(x - 3) = 0

      Finally

                4x = 0        x + 3 = 0           x -3 = 0

                x = 0/4        x₂ = -3               x₃ = 3

                x₁ = 0

Answer 2

Answer:

$x=0\text{ or }x=-3\text{ or }x=3$

Step-by-step explanation:

We have been an equation $4x^3=36x$. We are asked to find the solutions for our given equation.

First of all, we will subtract $36x$ from both sides as:

$4x^3-36x=36x-36x$

$4x^3-36x=0$

Let us factor the given equation.

$4x(x^2-9)=0$

Use difference of squares:

$4x(x^2-3^2)=0$

$4x(x+3)(x-3)=0$

Using zero product property, we will get:

$4x=0\text{ or }(x+3)=0\text{ or }(x-3)=0$

$x=0\text{ or }x=-3\text{ or }x=3$

Therefore, the solutions for our given equation would be $x=0\text{ or }x=-3\text{ or }x=3$.