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spin [16.1K]
3 years ago
7

Gloria has 11 markers in a backpack. One of them is purple and one is gray. Find the probability Gloria will reach into the back

pack without looking and grab the purple marker and then reach in a second time and grab the gray marker. Express your answer as a fraction in simplest form.
Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
8 0

Answer:

Step-by-step explanation:

She has 1 in 11 chances of getting the purple one

One of her choices is gone after she takes out the purple one. She has a 1 in 10 chance of taking out the gray one.

1/11 * 1/10 = 1/110

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Isi drilled a hole that is 5/9 inch wide.she has a screw that is 5/6 inch wide.is the hole wide enough to fit the screw
koban [17]

NO the screw is to big to fit

The variable in non simplified form will be

5/9 is 10/18

5/6 is 15/18

Since 5/6 is larger the screw will not be able to fit in a smaller hole.

Hope this helped!

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Are you good at math then here
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Answer:

see below

Step-by-step explanation:

The term -2t suggests that there are "t" of something that costs $2, or there are 2 of something that costs "t" dollars. The options marked include both interpretations.

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2x(squared) + 5 - 2<br><br> What is the answer to this trinomial?
Juliette [100K]
The answer is <span>2x + 3. 
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3 years ago
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Witch of the following are the factors of 4b^2 - 16?
luda_lava [24]
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3 years ago
Pls show work! questions on pic
Lena [83]

Answer:

a.(10,23)

b.(7,30)

e.(20,20)

Step-by-step explanation:

We are given that

x=Width of garden

y=Length of garden

According to question

x\geq 5

y\geq 20

Perimeter of rectangle=2(x+y)

Where x=Width  of rectangle

y=Length of rectangle

Fencing used =2(x+y)

2(x+y)\leq 80

First we change inequality  into equality

x=5...(1)

y=20...(2)

2(x+y)=80

x+y=40...(3)

Substitute x=0 in equation (3)

y=40

Substitute y=0  in equation (3)

x=40

Substitute x=0 and y=0 in equation (3)

2(x+y)\leq 80

0\leq 80

It is true. Therefore, the  shaded region below the line.

0\geq 5

0\geq 20

These are false equation .Therefore, the shaded region above the line.

Substitute x=5 in equation (3)

5+y=40

y=40-5=35

Substitute y=20 in equation (3)

x+20=40

x=40-20=20

Intersection point of equation (1) and (3) is (5,35) and intersect point of equation (2) and (3) is (20,20).

Now,

a.(10,23)

Substitute in

2(x+y)\leq 80

2(10+23)\leq 80

66\geq 80

10>5 and 23>20

it satisfied all inequality.

Hence, it is a solution.

b.(7,30)

7>5

30>20

2(7+30)=74

it satisfied all inequality.

Hence, it is a solution.

c.(18,25)

18>5

25>20

2(18+25)=86>80

It does not satisfied third inequality

Hence, it is not a solution.

d.(8,35)

8>5

35>20

2(8+35)=86>80

It does not satisfied third inequality

Hence, it is not a solution.

e.(20,20)

2(20+20)=80

20>5

20=20

it satisfied all inequality.

Hence, it is a solution.

4 0
3 years ago
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