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Effectus [21]
2 years ago
7

Write an equation of the line that passes through (1, 2) and is parallel to the line y = -52 +4.

Mathematics
1 answer:
jekas [21]2 years ago
5 0

Answer:

gfgdf

Step-by-step explanation:

dfhdf

You might be interested in
​
hjlf
4x - 3y + 20 = 0....4x - 3y = -21

4x - 3y = -21.....multiply by -2
5x - 6y = -25
----------------
-8x + 6y = 42 (result of multiplying by -2)
5x - 6y = -25
---------------add
-3x = 17
x = -17/3

this system of equations has 1 solution
4 0
3 years ago
Which numbers are solutions of the inequality?<br><br> x &gt; –5; –7, –5, –1
yanalaym [24]

Answer:

-1 is the only answer that is greater than -5

3 0
2 years ago
Which equation accurately represents this statement? Select three options. Negative 3 less than 4.9 times a number, x, is the sa
Svetllana [295]

Equations b,c, and e accurately represent this statement.

<h3>What is the equation?</h3>

A mathematical statement consisting of an equal symbol between two algebraic expressions with the same value is known as an equation.

The three equation accurately represents this statement is;

4.9 x-(-3) = 12.8

3+ 4.9 x = 12.8

12.8 = 4.9 x +3

Hence, equations b,c, and e accurately represent this statement.

To learn more, about equations, refer;

brainly.com/question/10413253

#SPJ1

6 0
2 years ago
How many times do 2 goes into 19
ser-zykov [4K]
Nine and a half times.
***
you can put it fully nine times. You reach 18 like this. But you have 1 more to go until 19! So, just cut the 2 in half to get 1, and put that in!
8 0
2 years ago
Read 2 more answers
(c). Under a set of controlled laboratory conditions, the size of the population P of a certain bacteria culture at time t (in s
Bezzdna [24]

(i) Since P(t) gives the population of the culture after t seconds, the population after 1 second is

P(1) = 3•1² + 3e¹ + 10 = 13 + 3e ≈ 21.155

In Mathematica, it's convenient to define a function:

P[t_] := 3t^2 + 3E^t + 10

(E is case-sensitive and must be capitalized. Alternatively, you could use Exp[t]. You can also specify that the argument t must be non-negative by entering a condition via P[t_ ;/ t >= 0], but that's not necessary.)

Then just evaluate P[1], or N[P[1]] or N <at symbol> P[1] or P[1] // N to get a numerical result.

(ii) The average rate of change of P(t) over an interval [a, b} is

(P(b) - P(a))/(b - a)

Then the ARoC between t = 2 and t = 6 is

(P(6) - P(2))/(6 - 2) ≈ 321.030

In M,

(P[6] - P[2])/(6 - 2)

and you can also include N just as before.

(iii) You want the instantaneous rate of change of P when t = 60 (since 1 minute = 60 seconds). Differentiate P :

P'(t) = 6t + 3e^t

Evaluate the derivative at t = 60 :

P'(60) = 6•60 + 3e⁶⁰ = 360 + 3e⁶⁰

The approximate value is quite large, so I'll just leave its exact value.

In M, the quickest way would be P'[60], or you can differentiate and replace (via ReplaceAll or /.) t with 60 as in D[P[t], t] /. t -> 60.

5 0
2 years ago
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