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3 years ago

Describe some of the problems faced by benthic organisms in the ocean. PLZ NEED HELP IMIDIATELY

1 answer:

8 0

Benthic organisms live on the ocean floor, where photosynthesis cannot occur. Since they cannot feed on any plants or living things that require photosynthesis to live, they must feed on either falling nutrients or on each other. due to the lack of a stable food source, life progresses slowly and survival isn't a promise.

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How are science and technology related?

aalyn [17]

One way you could think about it is that you used science of electronics to develop the technology of a computer
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3 years ago

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A scientist would use a balance to measure

GrogVix [38]

Answer is B

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4 years ago

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A merry-go-round with a a radius of R = 1.99 m and moment of inertia I = 194 kg-m2 is spinning with an initial angular speed of

Aleksandr [31]

Answer:

Part 1)

$L_1 = 185.2 kg m^2/s^2$

Part 2)

$L_2 = 663.07 kg m^2/s^2$

Part 3)

$L = 663.07 kg m^2/s^2$

Part 4)

$\omega = 1.83 rad/s$

Part 5)

$F_c = 453.6 N$

Explanation:

Part a)

Initial angular momentum of the merry go round is given as

$L_1 = I \omega$

here we know that

$I = 194 kg m^2$

$\omega = 1.47 rad/s^2$

now we have

$L_1 = 194 \times 1.47$

$L_1 = 185.2 kg m^2/s^2$

Part b)

Angular momentum of the person is given as

$L = mvR$

so we have

$m = 68 kg$

$v = 4.9 m/s$

R = 1.99 m

so we have

$L_2 = (68)(4.9)(1.99)$

$L_2 = 663.07 kg m^2/s^2$

Part 3)

Angular momentum of the person is always constant with respect to the axis of disc

so it is given as

$L = 663.07 kg m^2/s^2$

Part 4)

By angular momentum conservation of the system we will have

$L_1 + L_2 = (I_1 + I_2)\omega$

$185.2 + 663.07 = (194 + 68(1.99^2))\omega$

$848.27 = 463.28 \omega$

$\omega = 1.83 rad/s$

Part 5)

Force required to hold the person is centripetal force which act towards the center

so we will have

$F_c = m\omega^2 R$

$F_c = 68(1.83^2)(1.99)$

$F_c = 453.6 N$

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3 years ago

A plane flies 600 kilometers away from its bad at 400 meters per second then flies back to its base at 600 meters per second. Wh

tester [92]

Seems to me that it flies 400 m/s there and 600 m/s back the same distance.
therefore the average of 400 and 600 is 500 m/s. The distance is the same so the normal formula of (d2-d1)/(t2-t1) is applicable.

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4 years ago

(No files or links) Which of the following is a defining property of gases?

MariettaO [177]

The answer for this is d

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4 years ago