We can use the ideal gas
equation which is expressed as PV = nRT. At a constant volume and number of
moles of the gas the ratio of T and P is equal to some constant. At
another set of condition, the constant is still the same. Calculations are as
follows:
T1/P1 = T2/P2
P2 = T2 x P1 / T1
P2 = 273 x 340 / 713
<span>P2 = 130 kPa</span>
Answer: image to much to type.
Explanation:
In 9 sec, it increases the angular velocity by (0.45 x 9) rad/s which will give us 4.05 rad/s
Now get the angular velocity and divide it 2pi = 4.05 by 2(pi) to give how many revolutions 4.05 rad is equivalent to = 0.6446 rps
Them, multiply this by 60 to get it from rps to rpm increase (0.6446 x 60)=38.676 rpm
Add this and the starting revolution frequency of 49 rpm to give: (49 rpm + 38.676 rpm) = 87.6760 rpm
Answer:
D. 12.4 m
Explanation:
Given that,
The initial velocity of the ball, u = 18 m/s
The angle at which the ball is projected, θ = 60°
The maximum height of the ball is given by the formula
h = u² sin²θ/2g m
Where,
g - acceleration due to gravity. (9.8 m/s)
Substituting the values in the above equation
h = 18² · sin²60 / 2 x 9.8
= 18² x 0.75 / 2 x 9.8
= 12.4 m
Hence, the maximum height of the ball attained, h = 12.4 m
