Given:
A square base pyramid whose base length is 10 in. and height of triangular surface is 4 in.
To find:
The surface area of the pyramid to the nearest whole number.
Solution:
A square base pyramid contains square base with edge 10 in. and 4 congruent triangles with base 10 in. and height 4 in.
Area of a square is
So, area of square base is 100 sq. in.
Area of a triangle is
So, area of each triangular surface is 20 sq. in.
Now, the total surface area of the pyramid is
Total area = Area of square base + Area of 4 congruent triangles.
Therefore, the area of the pyramid is 180 sq. in.
Calculation:
(Length) (width) (height)
(2w+4) (w) (18-w) = 1152
(2w^2+4w) (18-w) = 1152
Distributive property:
36w^2 -2w^3+72w-4w^2 =1152
Remember to use FOIL method:
-2w^3 +32w^2+72w-1152 =0
Like terms:
-2(w^3-16w^2-36w+576) = 0
Factor it by 2:
w^3 -16w^2-36w+576 =0
Simplify:
w^2(w-16)-36(w-16) =0
(w^2-36) (w-16) = 0
w= -6,6,16
Width:
w = 6,16
Since width is 16, then the height should be less than the width (18-16=2)
Length of gift bag: 2(6)+4
=16 inches.
Width of the bag: 6
Height of the bag: 18-6
12 inches.
Answer: 16, 6 and 12 inches.
The answer is D because all you have to do is subtract the two numbers in the water tank.
Given:
Required: Parametric equation of y.
Explanation:
Substitute 4+t for y into the equation of x.
So, the parametric equation for x is x = 4t+19.
Final Answer: The parametric equation of x is x = 4t + 19.