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aliina [53]
3 years ago
14

What is a statement that is true for any number or variable?

Mathematics
2 answers:
Gnesinka [82]3 years ago
3 0
They all have the common factor of 1

any number can be multiplied by one to get that same number.
I hope this helps!
masha68 [24]3 years ago
3 0
You can use any number
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All but 4 of the counselors at a certain summer camp have a sailing certification, first aid certification, or
inysia [295]
Jdjdhdhdjdjdjjzhdbsjduxhdbducj
5 0
3 years ago
Label the equations in number 5-7 as True or False:
kkurt [141]

Answer:

{ \rm{ {(7}^{1}) ^{9    }  = 7 {}^{5} \times  {7}^{5}  :   \: { \tt{ \red{false}}} }} \\{ \boxed{ \mathfrak{correction \dashrightarrow \: ( {7}^{1}) {}^{9}  =  {7}^{9}  }}} \\ \\  { \rm{ \frac{ {y}^{13} }{ {( {y}^{2}) }^{6} } =  {y}^{ - 10}   \times  {y}^{9}  :  \:{ \tt { \red{false}}}}} \\ { \boxed{ \mathfrak{correction \:  \dashrightarrow \:  { \rm{{y}^{1} }}}}} \\  \\ { \rm{ {b}^{4}  \times  {b}^{ - 6}  =   \frac{ {b}^{1}  \times  {b}^{3} }{ {b}^{6} } }} \:  :  \: { \tt{ \green{true}}}

8 0
3 years ago
Read 2 more answers
Prove 2^n > n for all n equal to or greater than 1. I mostly need help with how to solve the problem when it is greater than
noname [10]
If n is an integer, you can use induction. First show the inequality holds for n=1. You have 2^1=2>1, which is true.

Now assume this holds in general for n=k, i.e. that 2^k>k. We want to prove the statement then must hold for n=k+1.

Because 2^k>k, you have

2^{k+1}=2\times2^k>2k

and this must be greater than k+1 for the statement to be true, so we require

2k>k+1

for k>1. Well this is obviously true, because solving the inequality gives 3k>1\implies k>\dfrac13. So you're done.

If you n is any real number, you can use derivatives to show that 2^n increases monotonically and faster than n.
7 0
3 years ago
Here is the graph of the sequence M define M recursively using function notation<br> 
aev [14]

The graph of the sequence M , we define M recursively using function notation

f(n+1)=f(n)-2

Given :

the graph of the sequence M

Lets write the recursive function using the given points

First point is (1,7) and second point is (2,5) then (3,3) and so on

For recursive function , we use the initial point (1,7)

when n=1, f(n)=7

the y values of the point are decreasing by 2. Common difference is -2

Recursive function is

f(n+1)=f(n)-diffeference \\f(n+1)=f(n)-2

where n=2,3,4...

Learn more : brainly.com/question/10676131

8 0
2 years ago
Tell whether the sequence is arithmetic. If it is, what is the common difference?
Ilya [14]
The answer is B. Yes; 4

Arithmetic sequence is the type of sequence of numbers which difference between each number will always remain constant
in the sequence above we could see the difference between one number with another is exactly 4:

15 + 4 = 19

19 + 4 = 23

23 + 4 = 27


7 0
3 years ago
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