Same here , like somebody please answer thanks
We have that
point C and point D have y = 0-----------> (the bottom of the trapezoid).
point A and point B have y = 4e ---------- > (the top of the trapezoid)
the y component of midpoint would be halfway between these lines
y = (4e+ 0)/2 = 2e.
<span>the x component of the midpoint of the midsegment would be halfway between the midpoint of AB and the midpoint of CD.
x component of midpoint of AB is (4d + 4f)/2.
x component of midpoint of CD is (4g + 0)/2 = 4g/2.
x component of a point between the two we just found is
[(4d + 4f)/2 + 4g/2]/2 = [(4d + 4f + 4g)/2]/2 = (4d + 4f + 4g)/4 = d + f + g.
</span>therefore
the midpoint of the midsegment is (d + f + g, 2e)
It would be 4/15 is greater.
4/15 = 26% wrong
3/10 = 30% wrong
Answer:
a = 2, b = 3.5
Step-by-step explanation:
Expanding
using Binomial expansion, we have that:
=


We have that the coefficients of the first two terms are 128 and -224.
For the first term:
=>
=> ![a = \sqrt[7]{128}\\ \\\\a = 2](https://tex.z-dn.net/?f=a%20%3D%20%5Csqrt%5B7%5D%7B128%7D%5C%5C%20%5C%5C%5C%5Ca%20%3D%202)
For the second term:

Therefore, a = 2, b = 3.5