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blondinia [14]
3 years ago
15

7 3/8 - 4/7 Estimate

Mathematics
1 answer:
DedPeter [7]3 years ago
6 0

Answer:

7\,\frac{3}{8}-\frac{4}{7} = 6\,\frac{45}{56}

Step-by-step explanation:

Let x = 7\,\frac{3}{8}-\frac{4}{7}, we proceed to simplify into a single rational number by algebraic means:

1) 7\,\frac{3}{8} -\frac{4}{7} Given

2) \left(\frac{56}{8}+\frac{3}{8}\right)-\frac{4}{7} Definition of mixed number/Associative property

3) \frac{59}{8}-\frac{4}{7}  \frac{a}{b} + \frac{c}{b} = \frac{a+c}{b}

4) \frac{413-32}{56} \frac{a}{b}+\frac{c}{d}

5) \frac{381}{56} Definition of subtraction

6) \frac{336}{56}+\frac{45}{56}  \frac{a}{b} + \frac{c}{b} = \frac{a+c}{b}

7) 6\,\frac{45}{56} Definition of mixed number/Result

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X/2−5=−12<br> I need to know how to get the answer to what X is
QveST [7]

Answer:

-14

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

x/2-5=-12

1/2x+-5=-12

1/2x-5=-12

Step 2: Add 5 to both sides.

1/2x-5+5=-12+5

1/2x=-7

Step 3: Multiply both sides by 2.

2*(1/2x)=(2)*(-7)

x=-14

8 0
3 years ago
Read 2 more answers
Last year, a comprehensive report stated that 28% of businesses in the northeast of Ohio were considered highly profitable. This
Alik [6]

Answer:

z=\frac{0.38 -0.28}{\sqrt{\frac{0.28(1-0.28)}{50}}}=1.575  

p_v =2*P(z>1.575)=0.115  

So the p value obtained was a very high value and using the significance level given \alpha=0.01 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of businesses were highly profitable is not significantly different from 0.28 or 28%.

Step-by-step explanation:

Data given and notation

n=50 represent the random sample taken

X=19 represent the businesses were highly profitable

\hat p=\frac{19}{50}=0.38 estimated proportion of businesses were highly profitable

p_o=0.28 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion of businesses were highly profitable is different from 0.28 or no, the system of hypothesis is.:  

Null hypothesis:p=0.28  

Alternative hypothesis:p \neq 0.28  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info required we can replace in formula (1) like this:  

z=\frac{0.38 -0.28}{\sqrt{\frac{0.28(1-0.28)}{50}}}=1.575  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(z>1.575)=0.115  

So the p value obtained was a very high value and using the significance level given \alpha=0.01 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of businesses were highly profitable is not significantly different from 0.28 or 28%.

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