Its not C
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The maximum speed of a boat at 30 feet length of water is 0.093 nautical miles/hour or knots.
<u>Step-by-step explanation:</u>
- The equation for the maximum speed, s is given by s²= (16/9)x
- where, x is the length of the water line in feet.
It is given that, the modeled equation s²= (16/9)x is used to find the maximum speed in knots or nautical miles per hour.
The question is asked to find the maximum speed when the length of the water is 30 feet.
Therefore, to find the maximum speed in 30 feet water, the given modeled equation is used. So, substitute the 30 feet in place of x.
<u>Now, calculating the maximum speed :</u>
s² = (16/9)(30)
s² = 480 / 9
s² = 53.3
Taking square root on both sides,
s = √53.3
s = 7.3
The maximum speed of a boat at 30 feet length of water is 7.3 nautical miles/hour or knots.
Answer:
1)
angle 2WZX = angle ZYX ( Since all angles and sides of a rhombus are equal)
ZYX = 2 x 29.5
59
2)
4x - 10 =90 (since all angles of a rhombus intersect at 90°)
x=90+10/4
x=100/4
x=25
hope this helps
<span>Width = 6
Length = 30
We know the perimeter of a rectangle is simply twice the sum of it's length and width. So we have the expression:
72 = 2*(L + W)
And since we also know for this rectangle that it's length is 6 more than 4 times it's width, we have this equation as well:
L = 6 + 4*W
So let's determine what the dimensions are. Since we have a nice equation that expresses length in terms of width, let's substitute that equation into the equation we have for the perimeter and solve. So:
72 = 2*(L + W)
72 = 2*(6 + 4*W + W)
72 = 2*(6 + 5*W)
72 = 12 + 10*W
60 = 10*W
6 = W
So we now know that the width is 6. And since we have an expression telling us the length when given the width, we can easily determine the length. So:
L = 6 + 4*W
L = 6 + 4*6
L = 6 + 24
L = 30
And now we know the length as well.</span>
Opposites.
Their sum is zero so they are called opposites.
