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slavikrds [6]
3 years ago
7

True or false A triangle with sides having measures of 3, 4,

Mathematics
2 answers:
Fofino [41]3 years ago
6 0

Answer:

False

Step-by-step explanation:

A commonly known Pythagorean Triple for a right triangle is a 3-4-5 triangle.  Something so close will not be a perfect right triangle, but may be close.

Tju [1.3M]3 years ago
6 0

Answer:

false

Step-by-step explanation:

This triangle does not fit with the Pythagorean Theorem which is used to find the dimensions of a right triangle. If the dimensions were 3,4,5 it would work because 3 squared plus 4 squared equals 25 and 5 squared is 25

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please help asap!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Phantasy [73]

Answer:

Area = 7.853981 in^2                (2.5 Pi)

Perimeter = 11.42478 in              (3.63Pi)

Step-by-step explanation:

Area

Lg semi circle area = Pi(2^2)(0.5) = 3.141593(4)0.5) = 6.283185 in^2

Sm semi circle area = Pi(1^2)(0.5) = 3.141593(2)(0.5) = 1.570796 in^2

added together = 7.853981 in^2

Perimeter

Lg semi circle perimeter = Pi(4)(0.5) + 2 = 8.283185 in

Sm semi circle perimeter = Pi(2)(0.5) = 3.141593 in

added together = 11.42478 in

5 0
3 years ago
Hey! yes you! can you help me with this? I will give brainliest! ​
KonstantinChe [14]

Answer:

the answer is h

Step-by-step explanation:

7 0
3 years ago
What if the experiment is repeated 1,000 times, then how many times could you expect to draw Ella's name?
hodyreva [135]

Answer:

i have no idea

Step-by-step explanation:

6 0
3 years ago
ELECTRICITY The impedance in one part of a series circuit is 1 + 3j ohms and the impedance in another part of the circuit is 7 -
TiliK225 [7]

Answer:

Total impedance in circuit = 8 - 2j ohms

Step-by-step explanation:

Given:

Circuit one = 1 + 3j ohms

Circuit two = 7 - 5j ohms

Find:

Total impedance in circuit

Computation:

Total impedance in circuit = Circuit one + Circuit two

Total impedance in circuit = 1 + 3j + 7 - 5j

Total impedance in circuit = 8 - 2j ohms

5 0
3 years ago
Find the value of x. Hint: the chords are congruent/equal (I will give 20 points)
Advocard [28]

\huge \purple{\tt{Answer:}}

If the chords are equal , then the measurement of both the chords will also be the same . That means ,

\sf {6x-7 =35} \\\\\ \implies \sf {6x = 35 +7} \\\\\ \implies \sf {6x=42} \\\\\ \implies \sf{x= {\dfrac{\bcancel {42}^7}{\bcancel{6}}}} \\\\\ \implies \sf{x=7}

5 0
2 years ago
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