Answer:
x-intercept:(2,0)
y-intercept:(0,-4)
Step-by-step explanation:
Answer:
-1
Step-by-step explanation:
This all comes down to the substitution. I am assuming that (4x2) is meant to be 4x^2 so I will solve as that.
4(-2)^2 = 4(4) = 16
4(-2) = - 8
-2(3)^2 = -2(9) = -18
3(3) = 9
16-8-18+9= -1
A = 8i + 6j
b = 4i + 5j
ab = (8i + 6j)(4i + 5j)
ab = 8i(4i + 5j) + 6j(4i + 5j)
ab = 8i(4i) + 8i(5j) + 6j(4i) + 6j(5j)
ab = 32i² + 40ij + 24ij + 30j²
ab = 32i² + 64ij + 30j²
ab = <32, 30>
The answer is D.
-2(2x-1)(x+3) = ((-2)2x - (-2)(-1))(x+3) = (-4x-2)(x+3)
Answer:
Step-by-step explanation:
The given data is 11, 77, 35, 5, 76, 34, 89, 92, 22
The total number of items in the data is 9. The width of each class interval would be gotten by dividing the difference between the minimum and maximum items in the data by the number of class intervals. From the information given,
Minimum item = 5
Maximum item = 92
Difference = 92 - 5 = 7
Class width = 87/10 = 8.7
By approximation, it is closest to 10
Therefore, the appropriate class group is 0 to 10
