All categories

4 years ago

Ninety percent of the students or 540 students attended a school assembly. How many students are there at the school

Mathematics

1 answer:

krok68 [10]4 years ago

6 0

if 540 is 90% or 0.9 then 0.1 or 10% is 1/9 of 540.

540/9 is 1/9 of 540, and 10% of the school's population. that makes 60

so 540 + 60 = 100% of the school assembly.

600 students

You might be interested in

A 5.5 ounce breadstick weighs the same as 16

givi [52]

Answer: top right

Step-by-step explanation: in order to seperate p, we need to multiply each side by 6, as this will make the right side just p. Then, since we mutiplied by 6 on the right side, we multiply by 6 on the left side too, so we get 5.5*6

8 0

3 years ago

The area of a square is 175 square centimeters. The length of its side is between what two values?

Lisa [10]

Answer:

13 and 14

Step-by-step explanation:

The area of a square can be found by length times width. In a square, length and width have the same value. By finding the square root of 175, you can find the length of each side.

8 0

3 years ago

Use the table of integrals, or a computer or calculator with symbolic integration capabilities, to find the indefinite integral.

nignag [31]

Answer:

$-\frac{3}{11}\ln(\cot t + \csc t)+C$

Step-by-step explanation:

We are given: $\int \frac{3}{x\sqrt{121-x^2}} dx$

We will use integration by parts.

$x = 11 \sin t\\dx = 11 \cos t \: dt$

$\int \frac{3}{x\sqrt{121-x^2}} dx=\int \frac{3* 11 \cos t \: dt}{11 \sin t\sqrt{121-121\sin^2 t}} =\int \frac{3* 11 \cos t \: dt}{11 \sin t*11\cos t}} =\\\\= \frac{3}{11} \int \csc t = -\frac{3}{11}\ln(\cot t + \csc t)+C$

4 0

4 years ago

Plz help, i will give brainliest?<br><br> what is 890,754 x 205,789

nikdorinn [45]

Answer:

183,307,374,906

3 0

3 years ago

Read 2 more answers

Which of the following inequalities matches the graph?

brilliants [131]

Hi there! The answer is D.

We're looking at the graph y = - 1. The area above this line is the shaded area, so the solution must be greater than (or equal to) -1. Therefore we're looking at
$y \geqslant - 1$

4 0

4 years ago

Read 2 more answers