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Pepsi [2]
3 years ago
14

When are the products of an equilibrium reaction favored? When the reaction is endothermic. When the equilibrium constant is lar

ge. When the macroscopic properties are constant. When the activation energy of the forward reaction is high. When the reverse reaction is favored.
Chemistry
2 answers:
allochka39001 [22]3 years ago
5 0

Answer:  option B. when the equilibrium constant is large.

Explanation:

PtichkaEL [24]3 years ago
3 0
Product are favored at ...


example 2A + 3B = 5C + D    if reaction is exothermic ....delta H = NEGATIVE)


A decrease  in temperature favors the forward reaction (more product formed)
as heat is considered as a product

For the exam I have given: A decrease in pressure (volume increases as pressure decreases) .... there are more number of moles on the product side (6 in all) .....so according to LCP decreasing pressure will revert back to increase pressure and to do that equilibrium position shifts to the right (product)

decreasing concentration of product will cause a disturbance in equilibrium position....and reaction will restore its equilibrium by shifting to the  right


(I believe its like this)
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What are duplet and octet elements ?Differentiate.​
Finger [1]
Octet means presence of a total of 8 electrons in its valence shell while in case of duplet only 2 electrons are present in valence shell.
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Sometimes described as a "chemical brother" of gaba (gamma-aminobutyric acid), which amino acid neurotransmitter acts in an exci
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4 0
3 years ago
Flammable materials, like alcohol, should never be
jarptica [38.1K]

Answer:

b.open flame because it is fundamental end of the alcohol mixes in with the flame then it will become a bigger fire

5 0
3 years ago
Displaement of ammonia from its salt
Dvinal [7]
Ill say <span>calcium hydroxide but hope this helps :)</span>
5 0
3 years ago
What is the boiling point of a solution containing 203 g of ethylene glycol (C2H6O2) and 1035 g of water? (Kb for water is 0.52
Andru [333]

Answer:

101,37°C

Explanation:

Boiling point elevation is one of the colligative properties of matter. The formula is:

ΔT = kb×m <em>(1)</em>

Where:

ΔT is change in boiling point: (X-100°C) -X is the boiling point of the solution-

kb is ebulloscopic constant (0,52°C/m)

And m is molality of solution (mol of ethylene glycol / kg of solution). Moles of ethylene glycol (MW: 62,07g/mol):

203g × (1mol /62,07g) = <em>3,27moles of ethlyene glycol</em>

<em />

Molality is: 3,27moles of ethlyene glycol / (1,035kg + 0,203kg) = 2,64m

Replacing these values in (1):

X - 100°C = 0,52°C/m×2,64m

X - 100°C = 1,37°C

<em>X = 101,37°C</em>

<em></em>

I hope it helps!

7 0
3 years ago
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