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Viefleur [7K]
3 years ago
13

An object exerts a reaction force when it _____.

Chemistry
2 answers:
lina2011 [118]3 years ago
8 0

Is pushed by another object - Gradpoint

VashaNatasha [74]3 years ago
7 0
Touch or pushed........
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Can you help me please..
Murrr4er [49]

Answer:

Using Charles law of Gas

Explanation:

7 0
3 years ago
Which is a resource that the National Park Service manages?
pantera1 [17]

Answer:

to preserve the integrity of the wildlife refuge, ecosystems and the endangered species.

Explanation:

A national park service manages

4 0
2 years ago
A chemist requires 0.802 mol Na2CO3 for a reaction. How many grams does this correspond to?
Komok [63]

Answer:

Ok:

Explanation:

So grams = mols*MolarMass. Here, MolarMass (MM) = 105.99g which can be found using the periodic table. mols is given to be 0.802. We can then plug in to get that it corresponds to 85.0g.

7 0
2 years ago
Keesha performed a chemical reaction and the products looked quite different from the reactants. She knew the amount of matter h
lakkis [162]

Answer:

the spotlight effect.

Explanation:

The spotlight effect is a tendency to think that people get noticed more often than they really do. It is an overestimation of the situation regarding the concern of getting observed. It concerns the self-confidence of an individual. For example, an individual feels that everybody in a party would notice him for a bad pair of shoes while in reality, it does not concern them.

As per the question, the overestimation of people's reaction is known as the spotlight effect.

5 0
2 years ago
A first order reaction has a rate constant of 0.543 at 25 c and 6.47 at 47
alukav5142 [94]

The activation energy Ea can be related to rate constant (k) at temperature (T) through the equation:

ln(k2/k1) = Ea/R[1/T1 - 1/T2]

where :

k1 is the rate constant at temperature T1

k2 is the rate constant at temperature T2

R = gas constant = 8.314 J/K-mol

Given data:

k1 = 0.543 s-1; T1 = 25 C = 25+273 = 298 K

k2 = 6.47 s-1; T = 47 C = 47+273 = 320 K

ln(6.47/0.543) = Ea/8.314 [1/298 - 1/320]

2.478 = 2.774 *10^-5 Ea

Ea = 0.8934*10^5 J = 89.3 kJ

5 0
3 years ago
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