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avanturin [10]
4 years ago
13

Is sand macromolecule or network solid? Thank you

Chemistry
1 answer:
Tanzania [10]4 years ago
3 0
A macromolecule is a molecule with lots and lots of atoms. (i.e. protein, nucleic acid...)
A network solid is <span>is a chemical compound where the atoms are "bonded by covalent bonds in a continuous </span>network<span> extending throughout the material."
A single grain of sand consists of, on average, </span><span>~50,000,000,000,000,000,000 atoms.
That's A LOT.
However, these atoms do bond in network covalent bonds.
But that means it's a covalent network solid.
The short answer is that sand is both a </span><span>macromolecular substance as well as a covalent network solid, so I would go with it's macromolecular but you can interpret that the way you want.</span>
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Which structure of the cell controls what goes in and comes out of the cell?
LenKa [72]
The Cell Membrane.

The Cell Membrane wraps around the entire cell and only allows certain things to pass through, blocking out potentially harmful things from the organelles within the cell.

Hope this helps!
7 0
3 years ago
375 mL of a 0.88 M potassium hydroxide solution is added to 496 mL of a 0.76 M cesium hydroxide solution. Calculate the pOH of t
AysviL [449]

Answer:

pOH of resulting solution is 0.086

Explanation:

KOH and CsOH are monoacidic strong base

Number of moles of OH^{-} in 375 mL of 0.88 M of KOH = \frac{0.88\times 375}{1000}moles = 0.33 moles

Number of moles of OH^{-} in 496 mL of 0.76 M of CsOH = \frac{0.76\times 496}{1000}moles = 0.38 moles

Total volume of mixture = (375 + 496) mL = 871 mL

Total number of moles of OH^{-} in mixture = (0.33 + 0.38) moles = 0.71 moles

So, concentration of OH^{-} in mixture, [OH^{-}] = \frac{0.71}{871}\times 1000M=0.82M

Hence, pOH=-log[OH^{-}]=-log(0.82)=0.086

8 0
3 years ago
I WILL GIVE BRAINLIEST!!!!!
Alexxx [7]
                                    HNO₃ + H₂S → S + NO + H₂<span>O

Assign Oxidation Number:

                                L.H.S                               R.H.S
           N in HNO</span>₃  =  +5                                     +2  =  N in NO
               S in H₂S  =  -2                                       0  =  S in S

Write Half cell Reactions:
Reduction Reaction:
                                 
3e⁻  +   HNO₃   →   NO      -------(1)
Oxidation Reaction:
                                  H₂S   →   S  +  2e⁻             -------(2)

Multiply eq. 1 with 2 and eq. 2 with 3 to balance electrons. 

                                          6e⁻  +   2 HNO₃   →   2 NO
                                    
                                             3 H₂S   →   3 S  +  6e⁻
                                                                                  Cancel e⁻s,
                                 ______________________________
                               
                             2 HNO₃  +  3 H₂S   →   2 NO  +  3 S  +  H₂O

Balance Oxygen Atoms by multiplying H₂O with 4, Hydrogen atoms will automatically get balance.

                            2 HNO₃  +  3 H₂S   →   2 NO  +  3 S  +  4H₂O


                                
4 0
4 years ago
Calculate the mass-to-mass ratio of 25.0 g of salt in 105 g of water. Work must be shown in order to earn credit.
Sveta_85 [38]

Answer:

0.23

Explanation:

  • It is known that, the mass to mass ratio of the salt to water

= (mass of salt / mass of water)

= (25.0 g / 105.0 g)

= 0.23

  • So, the answer is 0.23

4 0
3 years ago
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