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Darya [45]
3 years ago
9

Bryan withdrew $60 from his bank account. If this is 15% of the money he had in his account, how much money was in his account b

efore the withdrawal?
Mathematics
1 answer:
bazaltina [42]3 years ago
3 0

Answer:

Bryan had 400$ in his bank account before he withdraw

Step-by-step explanation:

60$ ---- 15%(set what you have)

x$ ------100%(set what you need)

(x$ x 15%) 15x =(60$ x 100%)6000( cris cross the sides)(the signs dont matter )

x=400

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Just 16 not the words below​
alekssr [168]

Answer:

Table F

Step-by-step explanation:

The equation is C = 0.75t. The variable c is for cost and t is for tickets. When we use substitution to solve the equation, we see that table F correctly represents the situation. In simpler terms, the equation is asking us to mutliply the cost PER ticket by the number of tickets.

0.75 * 1 = 0.75

0.75 * 2 = 1.50

0.75 * 3 = 2.25

0.75 * 4 = 3

And so on. As we can see, the only table that shows these values is in fact table F.

Hope this helps!

8 0
3 years ago
A triangle has a base of 12 cm and a height of 10 cm. Use the expression 1/2 base height to find the area of the triangle
Sergio [31]

Answer:

Area: 60

Step-by-step explanation:

1. Multiply the base and the height which are 12 cm and 10 cm.

2. The multiply that product by 1/2 or you can divide it by 2 to get the area of the triangle.

5 0
3 years ago
*cries* i need help :(
maria [59]

Answer:

choice B

Step-by-step explanation:

the war was fought in paterots homes because they had know were else to go

7 0
3 years ago
Which expressions are equivalent to x + 2y + x + 2?
Pani-rosa [81]

Answer:

none of the above im pretty sure

Step-by-step explanation:

6 0
3 years ago
Use the diagram to complete the statement. Triangle J K L is shown. Angle K J L is a right angle. Angle J K L is 52 degrees and
zzz [600]

Answer:

\bold{sin(38^\circ)=cos(52^\circ)}

Step-by-step explanation:

Given that \triangle KJL is a right angled triangle.

\angle JKL = 52^\circ\\\angle KLJ = 38^\circ

and

\angle KJL = 90^\circ

Kindly refer to the attached image of \triangle KJL in which all the given angles are shown.

To find:

sin(38°) = ?

a) cos(38°)

b) cos(52°)

c) tan(38°)

d) tan(52°)

Solution:

Let us use the trigonometric identities in the given \triangle KJL.

We have to find the value of sin(38°).

We know that sine trigonometric identity is given as:

sin\theta =\dfrac{Perpendicular}{Hypotenuse}

sin(\angle JLK) = \dfrac{JK}{KL}\\OR\\sin(38^\circ) = \dfrac{JK}{KL}....... (1)

Now, let us find out the values of trigonometric functions given in options one by one:

cos\theta =\dfrac{Base}{Hypotenuse}

cos(\angle JLK) = \dfrac{JL}{KL}\\OR\\cos(38^\circ) = \dfrac{JL}{KL}....... (2)

By (1) and (2):

sin(38°) \neq cos(38°).

cos(\angle JKL) = \dfrac{JK}{KL}\\OR\\cos(52^\circ) = \dfrac{JK}{KL} ...... (3)

Comparing equations (1) and (3):

we get the both are same.

\therefore \bold{sin(38^\circ)=cos(52^\circ)}

6 0
3 years ago
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