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kari74 [83]
3 years ago
12

" class="latex-formula"> > 4 solve the inequality with working for brainlest
Mathematics
1 answer:
Ainat [17]3 years ago
3 0

Answer:

Step-by-step explanation:

You might be interested in
What is the result of subtracting the second equation from the first?
Ronch [10]

Answer:

-5x + 0y = -11

The y terms are eliminated

Step-by-step explanation:

- 4x – 2y = -2

X - 2y = 9

We want to subtract the second equation from the first

Distribute a minus sign to all the terms in the second equation

- 4x – 2y = -2  

X - 2y = 9

= (-5x + 0y = -11)

6 0
3 years ago
NO ONE IS HELPING PLEASE. Find the value of x in each case! IF U GET THIS I WILL MARK BRAINLIEST. 25 POINTS ON THE LINE! Thank y
Murrr4er [49]

Answer:

11  

Step-by-step explanation:  

Use corresponding angles.  

Angle FBC is 180 - 147 which is 33.  

This means x is 180 - 33 - Angle EBA.  

EBA is 180 - 4x.  

x = 180 - 33 - (180 - 4x)  

x = 180 - 33 - 180 + 4x  

-3x = 180 - 33 - 180  

-3x = -33  

3x = 33  

x = 11  

Please mark brainliest.

6 0
2 years ago
TIME REMAINING
mars1129 [50]

Answer:

A pint of veggies is approximately $1.75

Step-by-step explanation:

(7 × 2.85) + 5v = 28.70. 19.95 + 5v = 28.70. 5v = 28.70 - 19.95. 5v = 8.75. v = 8.75/5. v = 1.75

Hope this helps!!

4 0
2 years ago
A circle is centered at the point (-7, -1) and passes through the point (8, 7).
Sergeu [11.5K]

we know the circle's center is at -7, -1, and we know the circle itself passes through 8,7, the distance from the center to a point on it is by definition its radius, therefore

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\\stackrel{center}{(\stackrel{x_1}{-7}~,~\stackrel{y_1}{-1})}\qquad (\stackrel{x_2}{8}~,~\stackrel{y_2}{7})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}\\\\\\\stackrel{radius}{r}=\sqrt{[8-(-7)]^2+[7-(-1)]^2}\implies r=\sqrt{(8+7)^2+(7+1)^2}\\\\\\r=\sqrt{15^2+8^2}\implies  r=\sqrt{225+64}\implies \boxed{r=17}

and since we know that x = -15 for such a point, then

\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2\qquad center~~(\stackrel{-7}{ h},\stackrel{-1}{ k})\qquad \qquad radius=\stackrel{17}{ r}\\\\\\\[x-(-7)]^2+[y-(-1)]^2=17^2\implies (x+7)^2+(y+1)^2=289\\\\\\\stackrel{\textit{since we know x = -15}}{(-15+7)^2+(y+1)^2=289}\implies (-8)^2+\stackrel{FOIL}{(y^2+2y+1^2)}=289\\\\\\64+y^2+2y+1=289\implies y^2+2y=224\implies y^2+2y-224=0\\\\\\(y+16)(y-14)=0\implies y=\begin{cases}-16\\14\end{cases}

since it's a circle, it touches x = -15 twice, check the picture below.

6 0
3 years ago
If-1 is a root of f), which of the following must be true?
ANEK [815]

Answer:

A factor of f(x) is (x + 1).

Step-by-step explanation:

When we put x+1= 0 then we  get the value x= -1

This value is then put into the function to find out whether it is a root or not. For a root  to exist it must not have a remainder or the remainder must be zero.

Suppose the function is

F(x)= 2x³ - 42x - 40

f(-1)= 2(-1)³ - 42(-1) - 40

f(-1)= -2 + 42- 40

f(-1)= 0

This gives -1 as the root of the function.

6 0
2 years ago
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