A triangle has vertices at B(−3, 0), C(2, −1), D(−1, 2). Which transformation would produce an image with vertices B″(−2, 1), C″
(3, 2), D″(0, −1)?
(x, y) → (x, −y), (x, y) → (x + 1, y + 1)
(x, y) → (−x, y), (x, y) → (x + 1, y + 1)
(x, y) → (x, −y), (x, y) → (x + 2, y + 2)
(x, y) → (−x, y), (x, y) → (x + 2, y + 2)
(x, y) → (x, −y), (x, y) → (x + 1, y + 1)
(x, y) → (−x, y), (x, y) → (x + 1, y + 1)
(x, y) → (x, −y), (x, y) → (x + 2, y + 2)
(x, y) → (−x, y), (x, y) → (x + 2, y + 2)
2 answers:
Answer:
A. (x, y) → (x,-y), (x, y) → (x + 1, y + 1)
Step-by-step explanation:
Plot points B, C and D on the coordinate plane (blue points in attached diagram).
1 transformation is reflection across the x-axis with the rule
(x,y)→(x,-y)
and it maps these points to
- B(-3,0)→B'(-3,0)
- C(2,-1)→C'(2,1)
- D(-1,2)→D'(-1,-2)
These image points are marked in green in attached diagram.
2 transformation is translation 1 unit to the right and 1 unit up with the rule
(x,y)→(x+1,y+1)
and it maps previous image points to
- B'(-3,0)→B''(-2,1)
- C'(2,1)→C''(3,2)
- D'(-1,-2)→D''(0,-1)
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