Answer:
4x^4 y^2 ∛x^2y^2
Step-by-step explanation:
A few of them are similar because of the sizes.
Answer:
k = 1 + sqrt(7/2) or k = 1 - sqrt(7/2)
Step-by-step explanation:
Solve for k over the real numbers:
4 k - 10/k = 8
Bring 4 k - 10/k together using the common denominator k:
(2 (2 k^2 - 5))/k = 8
Multiply both sides by k:
2 (2 k^2 - 5) = 8 k
Expand out terms of the left hand side:
4 k^2 - 10 = 8 k
Subtract 8 k from both sides:
4 k^2 - 8 k - 10 = 0
Divide both sides by 4:
k^2 - 2 k - 5/2 = 0
Add 5/2 to both sides:
k^2 - 2 k = 5/2
Add 1 to both sides:
k^2 - 2 k + 1 = 7/2
Write the left hand side as a square:
(k - 1)^2 = 7/2
Take the square root of both sides:
k - 1 = sqrt(7/2) or k - 1 = -sqrt(7/2)
Add 1 to both sides:
k = 1 + sqrt(7/2) or k - 1 = -sqrt(7/2)
Add 1 to both sides:
Answer: k = 1 + sqrt(7/2) or k = 1 - sqrt(7/2)
We have
First we will factorize the function
The domain is
In this case, we have two vertical asymptotes
x-2=0
x=2
x-3=0
x=3
ANSWER
The domain is
The vertical asymtotes
x-2=0
x=2
x-3=0
x=3
Answer:
Hi there!
Your answer is:
<em>8</em><em>.</em><em>6</em><em> </em><em>units</em>
Step-by-step explanation:
The distance formula is
√ ( (x2-x1)^2 + (y2-y1)^2 )
In your points:
A (-3, -2)
-3 is x1
-2 is y1
B (4, -7)
4 is x2
-7 is y2
Plug in to distance formula
√ ( 4-( -3))^2 + ( -7 - (-2))^2
√ (4+3)^2 + (-7+2)^2
√ (7^2) + ( -5)^2
√ 49 + 25
√ 74
This equals roughly 8.6 units!
