Answer:
a)
b)
Explanation:
The gravitational force on the satellite is calculated with Newton's Gravitation Law:
Where 
is Earth's mass, 
is the satellite mass, 
is the distance between their centers, where 
is the height of the satellite (from Earth's surface) and 
is Earth's radius, and 
is the gravitational constant.
a) With these values we then have:
b) And the fraction this force is of the satellite’s weight <em>W=mg</em> is:
I will answer both versions assuming what you want to know is the distance it travels up from and over the ground. and how long until it reaches space. 540 meters per second up and over. to reach space which is 100km above sea level, it would take about 5400 minutes
<span>Orbital radius would decrease because the gravitational pull would increase.</span>
Both the answers from "Big D" and "N9KXF" are correct, but not complete. There is one aspect that needs to be remembered for AC power - the phase relationship between the voltage and current.
<span>For AC power, the more complete equation for power is P = V * I * cosx, where x is the phase angle between voltage and current. </span>
<span>If the phase angle between voltage and current is 90 degrees, then even though current may be flowing, the total power over a cycle would be zero. Reactive elements like inductors and capacitors have a 90degree phase relationship between voltage and current. They do not "dissipate" energy. They store energy and give it back during different parts of the AC cycle. </span>
