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TEA [102]
3 years ago
12

A good refrigerant must have a high boiling point. Question 5 options: True False

Physics
2 answers:
Liono4ka [1.6K]3 years ago
5 0

Answer:

true a good refrigiant needs a high boiling point

NeTakaya3 years ago
3 0

A good refrigerant must have a high boiling point is FALSE.

<u>Explanation: </u>

It has the low boiling point.  It should have the ability to turn into gas in absorption of heat.

If the refrigerant need to be good and ideal must have the boiling point low and freezing point also low. The low boiling point makes the refrigerant to be good as it needs to boil when the temperature crosses the limit.

It has the high critical pressure and temperature in order to avoid the large power requirements of the compressor in the refrigerator.

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Two forces act on the screw eye. If F = 600 N, determine the magnitude of the resultant force and the angle θ if the resultant f
kobusy [5.1K]

Answer:

how to solve this problem ???????

5 0
3 years ago
Which object has the least amount of kinetic energy? a car driving down a road a soccer ball rolling down a hill a bicycle locke
mars1129 [50]
<span> a bicycle locked to a bike rack im pretty sure</span>
7 0
3 years ago
Read 2 more answers
Suppose a skydiver (mass = 75 kg) is falling toward the Earth. When the skydiver is 100 m above the Earth he is moving at 60 m/s
Andrej [43]

Answer:

  Potential energy = 73.575 kJ

  Kinetic energy = 135kJ

  Total mechanical energy = 208.575 kJ

Explanation:

   The potential energy of a body is given by the expression, PE = mgh, where m is the mass of the body, g is the acceleration due to gravity value and h is the height of the body.

  The kinetic energy of a body is given by KE=\frac{1}{2} mv^2, where v is the velocity and m is the mass of body.

  Total mechanical energy = Kinetic energy + Potential energy

  KE=\frac{1}{2} mv^2=\frac{1}{2} *75*60^2= 135000J = 135kJ

  PE = mgh = 75*9.81*100 = 73575 J = 73.575 kJ

  Total mechanical energy = Kinetic energy + Potential energy = 135+73.575

                                             = 208.575 kJ    

4 0
3 years ago
Given the initial wavefunction Ψ (x, 0) = Axexp (-k x) withx&gt; 0 andk&gt; 0, and Ψ (x, 0) = 0 forx &lt;0, what value must A ta
madam [21]

Answer with explanation:

The Normalization Principle states that

\int_{-\infty }^{+\infty }f(x)dx=1

Given

f(x)=xe^{-kx}(x>0\\\\0(x

Thus solving the integral we get

\int_{0 }^{+\infty }A\cdot xe^{-kx}dx=1\\\\A\int_{0 }^{+\infty }\cdot xe^{-kx}dx=1

The integral shall be solved using chain rule initially and finally we shall apply the limits as shown below

I=\int xe^{-kx}dx\\\\x\int e^{-kx}dx-\int \frac{d(x)}{dx}\int e^{-kx}dx\\\\-\frac{xe^{-kx}}{k}-\int 1\cdot \frac{-e^{-kx}}{k}\\\\\therefore I=\frac{e^{-kx}}{k}-\frac{xe^{-kx}}{k}

Applying the limits and solving for A we get

I=\frac{1}{k}[\frac{1}{e^{kx}}-\frac{x}{e^{kx}}]_{0}^{+\infty }\\\\I=-\frac{1}{k}\\\\\therefore A=-k

3 0
3 years ago
Imagine you use Nitrogen as your gas. If you have the cold side as cold as you can without liquefying it (78 K), and run the hot
alina1380 [7]

Answer:

The efficiency of a Stirling engine is 74%

Explanation:

Given:

Temperature of gas when it is cold T_{1} = 78 K

Temperature of gas when it is hot T_{2} = 300 K

The efficiency of a stirling engine,

  \eta =1 - \frac{T_{1} }{T_{2} }

  \eta = 1- \frac{78}{300}

  \eta = 1-0.26

  \eta = 0.74

∴ \eta = 74 \%

Therefore, the efficiency of a Stirling engine is 74%

5 0
3 years ago
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