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TEA [102]
3 years ago
12

A good refrigerant must have a high boiling point. Question 5 options: True False

Physics
2 answers:
Liono4ka [1.6K]3 years ago
5 0

Answer:

true a good refrigiant needs a high boiling point

NeTakaya3 years ago
3 0

A good refrigerant must have a high boiling point is FALSE.

<u>Explanation: </u>

It has the low boiling point.  It should have the ability to turn into gas in absorption of heat.

If the refrigerant need to be good and ideal must have the boiling point low and freezing point also low. The low boiling point makes the refrigerant to be good as it needs to boil when the temperature crosses the limit.

It has the high critical pressure and temperature in order to avoid the large power requirements of the compressor in the refrigerator.

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Explain why pulleys are in the lever family.
Aleks04 [339]

Answer:

The leverage or mechanical advantage of pulleys is less obvious, but you can "gang" multiple pulleys together into two sets (blocks) and run the ropes back and forth between the two sets to increase the number of lengths of rope running between them. One end of the rope is connected (fixed) to one of the blocks, and you get to pull on the other end after it is passed back and forth between the blocks of pulleys. This is sometimes called a block and tackle arrangement. With a hook on each side of the block set, you can move a heavy load much like levers do, by multiplying the force. You have to pull more rope just like you have to move a lever more on one side of the fulcrum as compared to the other. When you get all the rope pulled out that you can, you can not move the load anymore because you have become "two-blocked" which means the two blocks are together. Credits to: Moin Khan

3 0
3 years ago
Calculate the rate of heat conduction through a layer of still air that is 1 mm thick, with an area of 1 m, for a temperature of
max2010maxim [7]

Answer:

The rate of heat conduction through the layer of still air is 517.4 W

Explanation:

Given:

Thickness of the still air layer (L) = 1 mm

Area of the still air = 1 m

Temperature of the still air ( T) = 20°C

Thermal conductivity of still air (K) at 20°C = 25.87mW/mK

Rate of heat conduction (Q) = ?

To determine the rate of heat conduction through the still air, we apply the formula below.

Q =\frac{KA(\delta T)}{L}

Q =\frac{25.87*1*20}{1}

Q = 517.4 W

Therefore, the rate of heat conduction through the layer of still air is 517.4 W

6 0
3 years ago
Read 2 more answers
.
Greeley [361]

Answer:

this is impossible for me

Explanation:

7 0
3 years ago
A vector has an x component of 25.0 units and a y
sammy [17]
Here is the answer to your question

8 0
3 years ago
how is the position of electrons involved in metallic bonding different from the position of electrons that form ionic and coval
Yuri [45]
While ionic bonds join metals to nonmetals, and covalent bonds join nonmetals to nonmetals, metallic bonds are responsible for the bondingbetween metal atoms. In metallic bonds, the valence electrons from the s and p orbitals of the interacting metal atoms delocalize.

I hope that this answer helps you out
7 0
3 years ago
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