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bekas [8.4K]
3 years ago
10

The term that describes the time when the sun’s are directly over the equator is:

Physics
2 answers:
sukhopar [10]3 years ago
5 0
An equinox is the moment in which the plane of Earth's equator passes through the center of the Sun
Zepler [3.9K]3 years ago
3 0
It is called the equinox
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A rocket ship leaves Earth's atmosphere. Its initial velocity is less than its final velocity. What is this an example of?
77julia77 [94]
I believe this would be an example of positive acceleration as the initial velocity of the rocket is less than the final velocity, indicating that the rocket is accelerating and thus is positive.
6 0
3 years ago
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Calculate the net force if the forces are parallel 4N 4N
iogann1982 [59]

Answer:

The net force is zero Newtons (0 N).

Explanation:

If the forces on one side is 4N and the forces on another side are 4N, the forces cancel out and you have a net force of zero. This means the object is at rest or is moving at a constant rate based on the question.

Hope this helps!

5 0
3 years ago
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A example of using a muscular strength?
DIA [1.3K]
An example of using muscular strength would be doing things like lifting weights and things like that. 
7 0
3 years ago
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As the distance of a sound wave from its source quadruples, how is the intensity changed?
Naddik [55]

d. it decreases by a factor of 16

3 0
4 years ago
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A 250-kN railroad car A is traveling at 40 m/s while a 550-kN freight car B is traveling at 10 m/s (both cars heading to the rig
Damm [24]

Answer:

the maximum deformation undergone by the spring = 47.46 cm

Explanation:

Using conservation of  momentum:

m_Av_A + m_Bv_B = (m_A+m_B )v

where:

m_A = \frac{250\ kN}{g}

v_A = 40

m_B = \frac{550\ kN}{g}

v_B =10

Then;

m_Av_A + m_Bv_B = (m_A+m_B )v

\frac{250*10^3}{9.81}*40 + \frac{550*10^3}{9.81}*10 = (\frac{800*10^3}{9.81} )v

1580020.387 = 81549.43935 \ v

v = \frac{1580020.387}{81549.43935}

v = 19.375 m/s

However ; using conservation of energy to determine the maximum deformation undergone by the spring ; we have:

\frac{1}{2} [m_Av_A^2 +m_Bv_B^2] =\frac{1}{2}[(m_A+m_B)v^2 + kx^2]

[m_Av_A^2 +m_Bv_B^2] =[(m_A+m_B)v^2 + kx^2]

[\frac{250*10^3}{9.81}*40^2 + \frac{550*10^3}{9.81}*10^2] =[ (\frac{800*10^3}{9.81} )*19.375^2 + 70 *10^6 \ * x^2]

x = 0.4746 m

x = 47.46 cm

Thus,  the maximum deformation undergone by the spring = 47.46 cm

3 0
4 years ago
Read 2 more answers
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