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Maksim231197 [3]
3 years ago
13

Alice is making a gold necklace. The length of the chain is

Mathematics
1 answer:
podryga [215]3 years ago
6 0

Answer:

30.31 inches.

Step-by-step explanation:

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What is 7/3 times 2/3 multiplied in simplest form
Sav [38]
Multiplying fractions is simple. You just multiply across so 7/3 x 2/3 is 14/9 and that is the simplest form.
4 0
2 years ago
Read 2 more answers
Given the function, f (x) = sq3x+3+3, choose the correct transformation.
iren2701 [21]

Answer:

B.

Step-by-step explanation:

First, let's start from the parent function. The parent function is:

f(x)=\sqrt{x}

The possible transformations are so:

f(x)=a\sqrt{bx-c} +d,

where a is the vertical stretch, b is the horizontal stretch, c is the horizontal shift and d is the vertical shift.

From the given equation, we can see that a=1 (so no change), b=3, c=-3 (<em>negative </em>3), and d=3.

Thus, this is a horizontal stretch by a factor of 3, a shift of 3 to the <em>left </em>(because it's negative), and a vertical shift of 3 upwards (because it's positive).

7 0
3 years ago
1. When given the expression 5^3, what should you do to solve?
UNO [17]

Answer:

its b) 5×5×5

Step-by-step explanation:

a) 5×3 is 15

b) 5×5×5 is 5^3 or in simple form its 125

c) 3×3×3×3×3 = 3^5 or in simple form its 243

You should solve 5^3 as

= 5×5×5

= 125

Plzz mark me as brainliest :)★

5 0
2 years ago
F divides HJ in the ratio 3:1. If H = (-11,7) and J = (5,3), what are the<br> coordinates of F?
Hatshy [7]

Answer:

The coordinates of HF are (1, 4)

Step-by-step explanation:

The parameters of the line are;

The coordinate of the end points are H = (-11, 7), and J = (5, 3)

The ratio by which the point F divides the line = 3:1

The segments in the line are HF, and FJ

Therefore;

The fraction of the length of HJ that is represented by HF = 3/(3 + 1) × HJ = 3/4 × HJ

HF = 3/4 × HJ

Which gives the coordinates of the point F as follows;

Coordinate of F = (-11 +(5 - (-11))×3/4, 7 + (3 - 7)×3/4) =  (1, 4)

The coordinates of F are (1, 4)

We check the length of HF, from the equation for the length to of a line to get;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

l_{HF} = \sqrt{\left (4-7  \right )^{2}+\left (1-(-11)  \right )^{2}} = \sqrt{\left (-3  \right )^{2}+\left (12  \right )^{2}} = 3\cdot \sqrt{17}

Similarly, we check the length of HJ, to get;

l_{HF} = \sqrt{\left (3-7  \right )^{2}+\left (5-(-11)  \right )^{2}} = \sqrt{\left (-4  \right )^{2}+\left (16  \right )^{2}} = 4\cdot \sqrt{17}

The length of HF = 3·√(17)

The length of HJ = 4·√(17)

Therefore, from HF = 3/4× HJ, we have;

HF = 3/4 × 4·√(17) = 3·√(17)

Therefore, the coordinates of HF are (1, 4)

7 0
3 years ago
What is the mass of 2.5 moles of carbon dioxide?
GarryVolchara [31]

Answer:

110 grams

Step-by-step explanation:

CO2 molecule is made up of Carbon (atomic mass =12) and oxygen (atomic mass=16).

So first finding the mass of 1 molecule of CO2 which is equals to

= mass of 1 carbon atom + masses of 2 oxygen atom, we get

= 12+(16*2)= 12+32= 44 a.m.u.

Now 1 molecule of CO2 has mass 44 amu so mass of 1 mole CO2 will be 44 grams.( 1 a.m.u.=1.6729*10^-33 grams. 1 mole = 6.022*10^23, so 44 a.m.u.=73.6076*10^-33 grams approx. For one mole CO2, 73.6076*10^-33*6.022*10^23 which is approximately equals to 44 grams. )

1 mole CO2= 44grams, so 2.5 moles = 44*2.5= 110 grams

So our answer is 110 grams.

lowkey hope this helped you, good luck whatever you need it for Imaooo

3 0
2 years ago
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