Question

Write an equation of a line that is perpendicular to y = 2/3 x + 8 and has a y-intercept of

Answer 1

Answer:

y = -3/2x + 2

Step-by-step explanation:

Since you know it has a point at (0, 2) - the y intercept, put those values into the equation and solve. To be perpendicular it seems the reciprocal of the slope with the opposite sign, so 2/3 is the original slope, and -3/2 becomes the new slope.

y = 2/3x + 8 becomes

2 = -3/2(0) + b  We substitute in the x and y values, but we have to figure out what the last number will be.

2 = 0 + b

b = 2

So put the whole equation together

y = -3/2x + 2