Answer:
C
Step-by-step explanation:
Hope I was able to help!! :)
Answer:
Step-by-step explanation:
∠ABC = ∠BCD { AB // CD; BC TRAVERSAL, alternate angles are equal}
∠ABC = 20
∠BCA = ∠BAC {angles opposite to equal sides are equal}
∠BCA = ∠BAC = x
x + x + 20 = 180
2x = 180 - 20
2x = 160
x = 160/2
x = 80
1/6 x 54 = 9
Hope this helps ;)
Two lines are perpendicular if and only if the product of their slopes is - 1.
So, you just need to find the slope of each line and find out the product of their slopes.
I will do one example for you.
L1: y = 3x + 5
L2: y = - 3x + 14
L3: y = -x/3 + 14
The slope of a line is the coefficient of the x.
So the slopes are:
L1: slope 3
L2: slope -3
L3: slope -1/3
So now multiply the slopes of each pair of lines:
L1 and L2: 3 * (-3) = - 9 => No, they are not perpendicular
L2 and L3: (-3) * (-1/3) = 1 => No, they are not perpendicular
L1 and L3: (3) * (-1/3) = -1 => Yes, they are penpendicular.
