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katrin [286]
3 years ago
13

Evaluate the equation below

Mathematics
1 answer:
meriva3 years ago
3 0

Answer:

-2

Step-by-step explanation:

2(x-4)+3x-x² for x = 3

is : 2(3-4) +3(3)-3² = -2  ... answer : B

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Write an equation that you can use to solve for the height of the triangle (x). Notice that the perimeter is 48 feet.
MArishka [77]
A. 48 = 12 + 20 + x

If you use this equation then you can do 12 + 20 = 32 and then you can do 48 - 32 = 16 so x = 16
7 0
2 years ago
A teacher reviews 4-1/2 papers per hour, how many papers will that teacher review in 6-1/3 hours
MrRa [10]

Answer:

28\frac{1}{2}\ papers

Step-by-step explanation:

step 1

Convert mixed numbers to an improper fractions

4\frac{1}{2}=\frac{4*2+1}{2}=\frac{9}{2}

6\frac{1}{3}=\frac{6*3+1}{3}=\frac{19}{3}

step 2

we know that

A teacher reviews 9/2 papers per hour

using proportion

Find how many papers will the teacher review in 19/3 hours

Let

x-----> the number of papers

(9/2)/1=x/(19/3)

x=(19/3)(9/2)

x=28.5\ papers

Convert to mixed numbers

28.5=28\frac{1}{2}\ papers

5 0
3 years ago
What is the value of tan(60°)?<br> A<br> 12<br> 30°<br> B<br> 60°<br> 14
iogann1982 [59]

Answer:

the answer is 1.7320508076

8 0
2 years ago
Steven measures how much milk his kitten consumes in cups every day for a week. The line plot displays the results. List the dat
Furkat [3]

Answer:

3 3/5

Step-by-step explanation:

You can see that Steven's cat drank 2/5, Then it drank 3/5. If you add those together, then you get 1. Then it drank 1/2 a cup of milk 4 times, that would equal 2. Then, she drank one more 3/5 cup of milk. Then you add all the whole numbers, which equals 3 then you have that 3/5 left over so its 3 3/5

                                                 

8 0
2 years ago
The water in a river moves south at 10 mi/hr. A motorboat travels due east at a speed of 20 mi/hr relative to the shore. Determi
weeeeeb [17]

Answer:22.36 mi/hr

Step-by-step explanation:

Given

water in a river moves south at (V_w)10 mi/hr

motorboat travels due to east at a speed of (V_b)20 mi/hr

Velocity of boat relative to the moving water V_{bw}

V_{bw}=V_b-V_w

V_{bw}=20i-(-10j)=20i+10j

Magnitude of V_{bw}=\sqrt{20^2+10^2}=\sqrt{500}

V_{bw}=10\sqrt{5} \approx 22.36 mi/hr

tan\theta =\frac{10}{20}

\theta =26.56^{\circ} with the x axis.

4 0
3 years ago
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