5. 1,000,000
6. 9,300
7. 5,070
8. 5, 280
9. 810
10. 220
11. 44,770
12. 76, 000
Those are a few answers for you. Try looking back at your notes (If you copied any) to figure out your problems :)
Answer:
(2,4)
Step-by-step explanation:
left( - ) and right( + ) (x axes)
up( + ) and down( - ) (y axes)
(5,2) just add
5 - 3 = 2
2 + 2 = 4
Answer :
(2,4)
Answer:
I assume you know Arithmetic Progression .
so, we have to find the first and last 4-digit number divisible by 5
first = 1000 , last = 9990
we have a formula, = a + (n-1)d
here, is the last 4-digit number divisible by 5.
n is the number of 4-digit even numbers divisible by 5
d is the common difference between the numbers, which is 10 in this case
a is the first 4-digit number divisible by 5
9990 = 1000 + (n-1)*10
899 = n-1
n = 900
Hence, there are 900 4-digit even numbers divisible by 5
Answer:
X^3 AS THE NUMERATOR 8 AS THE DENOMINATOR
Step-by-step explanation:
X^6= 3^12
(X^6) ^1/6. = (3^12)^1/6
X=9