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LiRa [457]
3 years ago
11

Many universities and colleges have instituted supplemental instruction (SI) programs, in which a student facilitator meets regu

larly with a small group of students enrolled in the course to promote discussion of course material and enhance subject mastery. Suppose that students in a large statistics course (what else?) are randomly divided into a control group that will not participate in SI and a treatment group that will participate. At the end of the term, each student’s total score in the course is determined.
a. Are the scores from the SI group a sample from an existing population? If so, what is it? If not, what is the relevant conceptual population?
b. What do you think is the advantage of randomly dividing the students into the two groups rather than letting each student choose which group to join?
c. Why didn’t the investigators put all students in the treatment group? Note: The article "Supplemental Instruction: An Effective Component of Student Affairs Programming" (J. of College Student Devel., 1997: 577–586) discusses the analysis of data from several SI programs.
Mathematics
1 answer:
aev [14]3 years ago
5 0

Answer:

Step-by-step explanation:

Let many universities and colleges have conducted supplemental instruction(SI) programs. In that a student facilitator he meets the students group regularly who are enrolled in the course to promote discussion of course material and enhance subject mastery.

Here the students in a large statistics group are classified into two groups:

1). Control group: This group will not participate in SI and

2). Treatment group: This group will participate in SI.

a)Suppose they are samples from an existing population, Then it would be the population of students who are taking the course in question and who had supplemental instruction. And this would be same as the sample. Here we can guess that this is a conceptual population - The students who might take the class and get SI.

b)Some students might be more motivated, and they might spend the extra time in the SI sessions and do better. Here they have done better anyway because of their motivation. There is other possibility that some students have weak background and know it and take the exam, But still do not do as well as the others. Here we cannot separate out the effect of the SI from a lot of possibilities if you allow students to choose.

The random assignment guarantees ‘Unbiased’ results - good students and bad are just as likely to get the SI or control.

c)There wouldn't be any basis for comparison otherwise.

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If pentagon OPQRS is dilated by a scale factor of seven over four from the origin to create O'P'Q'R'S', what is the ordered pair
GrogVix [38]

Answer:

The order pair of point Q' is (-21/4 , -7/2)

Step-by-step explanation:

* Lets explain the dilation

- A dilation is a transformation that changes the size of a figure.  

- The figure can become larger or smaller, but the shape of the

 figure does not change.  

- The scale factor, measures how much the image will be larger

 or smaller  

- If the scale factor greater than 1, then the image will be larger

- If the scale factor between 0 and 1, then the image will be smaller

- The center of dilation is a fixed point in the plane about which all

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* Lets solve the problem

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- The image of the pentagon after the dilation is O'P'Q'R'S'

∵ The coordinates of the vertices of the pentagon OPQRS are

  O (-1 , 2) , P (-5 , 3) , Q (-3 , -2) , R (2 , 1) , S (2 , 5)

- To find the image of each point after the dilation multiply each

  coordinates of the points by the scale factor of dilation

∵ The scale factor is 7/4

∵ The coordinates of point Q are (-3 , -2)

∴ The image of point Q after dilation is (-3 × 7/4 , -2 × 7/4)

∴ The image of point Q after dilation is (-21/4 , -7/2)

∵ Q' is the image of Q

∴ Q' = (-21/4 , -7/2)

* The order pair of point Q' is (-21/4 , -7/2)

5 0
4 years ago
Read 2 more answers
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