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HACTEHA [7]
3 years ago
13

What is the equation of the line that passes through the points (15, 19) and (-2, 9)

Mathematics
1 answer:
shusha [124]3 years ago
6 0
I believe the equation of the line that passes through the points can be seen on the graph. Hope it helps :)
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Solve for y and x<br> 2+3x-1=4y <br> And <br> 2x-3=y
Natasha_Volkova [10]

Answer:

x = 2.6, y = 2.2

Step-by-step explanation:

if 4y = 2 + 3x - 1 and

y = 2x - 3,

4y = 2 + 3x -1 and 4y = 8x - 12 so

8x - 12 = 2 + 3x - 1

so 5x - 12 = 1,

5x = 13,

x = 2.6

If x = 2.6,

y = 5.6 - 3

so y = 2.2

Please mark me as Brainliest!

6 0
2 years ago
Which statement is true?
meriva

Answer:

The correct answer is A I believe . . .

8 0
2 years ago
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What is the relation of 2 parallel lines in terms of their slope?
mixas84 [53]
The slopes of two parallel lines are equal! They are identical to one another
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2 years ago
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Consider the initial value problem:
Inessa [10]

Answer:

\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2

Step-by-step explanation:

The given initial value problem is;

y''-5y'+6y=-5\sin(2t)---(1)\\y(0)=-5,y'(0)=2

Let

u(t)=y(t)----(2)\\v(t)=y'(t)----(3)

Differentiating both sides of equation (1) with respect to t, we obtain:

u'(t)=y'(t)---(4)\\ \\\implies u'(t)=v(t)---(5)

Differentiating both sides of equation (2) with respect to t gives:

v'(t)=y''(t)----(6)

From equation (1),

y''=5y'-6y-5\sin(2t)\\y''=5v(t)-6u(t)-5\sin(2t)\\\implies v'(t)=5v(t)-6u(t)-5\sin(2t)----(7)

Putting t=0 into equation (2) yields

u(0)=y(0)\\\implies u(0)=-5

Also putting t=0 into equation (3)

u'(0)=y'(0)\\u'(0)=2

The system of first order equations is:

\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2

3 0
3 years ago
Which ordered pair is a solution for 3x + 4y &lt; 12?
Andre45 [30]

Answer:

D, (1,2)

Step-by-step explanation:

It all comes down to substitution. In this case the coefficient of x is 3 and the coefficient of y is 4. The format of these coordinates being (x,y).

1. Plug in your x value (1 in this circumstance) and solve:

3(1) + 4y < 12

3 + 4y < 12

2. Plug in your y value (2 in this circumstance) and solve:

3 + 4(2) < 12

3 + 8 < 12

3. Solve

3 + 8 = 11

11 < 12

5 0
2 years ago
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