Answer:
Value of x using quadratic formula (x = -4) and (x = -5)
Step-by-step explanation:
Given:
Equation
x² + 9x + 20 = 0
Find:
Value of x using quadratic formula
Computation:
Quadratic formula = [-b±√b²-4ac] / 2a
Given equation;
x² + 9x + 20 = 0
a = 1 , b = 9 , c = 20
By putting value
[-9±√9²-4(1)(20)] / 2(1)
[-9±√81-80] / 2
[-9±√1] / 2
(-9 + 1) / 2 , (-9 - 1) / 2
-8 / 2 , 10 / 2
-4 , - 5
Value of x using quadratic formula (x = -4) and (x = -5)
Answer:
I wish i could help but I'm only in the 5 grade but I wish you best of luck
Step-by-step explanation:
sorry wish I could help
The approximate area of the decagon with a side of 8cm comes to be 492.40 cm².
The side of the regular decagon = 8cm
<h3>What is a regular decagon?</h3>
A regular decagon is a polygon with 10 sides that are equal to each other.
The area of a regular decagon with side a is:

So, the area A of the regular decagon with a side of 8cm:


A=492.40 cm²
Therefore, the approximate area of the decagon is 492.40 cm².
To get more about the decagon visit:
brainly.com/question/19899848