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earnstyle [38]
3 years ago
12

What is .85 (85 repeating) as a fraction

Mathematics
1 answer:
mojhsa [17]3 years ago
6 0
.85 repeating as a fraction is
\frac{85}{100 }
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The square root of 12 is irrational.<br><br> True<br> False
dalvyx [7]
True.

The square root of 12:   √12 = 3.464101......

This continues indefinitely and can not be represented as a ratio of two integers.

So it is not rational, that is irrational.
7 0
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A man spent 58% of his income and the amount of money left was $210. Find his income​
professor190 [17]

Answer:

500 $

Step-by-step explanation:

\frac{42\%}{210}=\frac{100\%}{x}

\frac{\frac{21}{50}}{210}=\frac{1}{x}

\frac{21}{50}x=210\\

\frac{21}{50}x\cdot \:50=210\cdot \:50\\

x=500

<3

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6 0
3 years ago
A recycling center pays 25 cents per aluminum can recycled at its facility. If Tracy recycles 5 aluminum cans there, how many do
USPshnik [31]
If Tracy recycles 5 and each is 25 cents

5 times 0.25 equals 1.25

She would get$1.25 for recycling 5 cans
3 0
3 years ago
Can someone please be nice enough and give me all the answer for these questions.
PSYCHO15rus [73]
1. 1/9 since you take all the "a"s in the words which is 2/18
2.2/9 same thing as above
3.18/18 since there is no "O" it's a trick question
4.3/9
5.5/6 since you don't count 6
6.1/2 and 1/2 coins are always 1/2 unless you flip twice
7.5/13
8.1/2 because 1,3,5 odd 2,4,6 even 
Hope that helps
8 0
3 years ago
Lines 3x-2y+7=0 and 6x+ay-18=0 is perpendicular. What is the value of a?
BlackZzzverrR [31]

Answer:

\boxed{\sf a = 9 }

Step-by-step explanation:

Two lines are given to us which are perpendicular to each other and we need to find out the value of a . The given equations are ,

\sf\longrightarrow 3x - 2y +7=0

\sf\longrightarrow 6x +ay -18 = 0

Step 1 : <u>Conver</u><u>t</u><u> </u><u>the </u><u>equations</u><u> in</u><u> </u><u>slope</u><u> intercept</u><u> form</u><u> </u><u>of</u><u> the</u><u> line</u><u> </u><u>.</u>

\sf\longrightarrow y = \dfrac{3x}{2} +\dfrac{ 7 }{2}

and ,

\sf\longrightarrow y = -\dfrac{6x }{a}+\dfrac{18}{a}

Step 2: <u>Find </u><u>the</u><u> </u><u>slope</u><u> of</u><u> the</u><u> </u><u>lines </u><u>:</u><u>-</u>

Now we know that the product of slope of two perpendicular lines is -1. Therefore , from Slope Intercept Form of the line we can say that the slope of first line is ,

\sf\longrightarrow Slope_1 = \dfrac{3}{2}

And the slope of the second line is ,

\sf\longrightarrow Slope_2 =\dfrac{-6}{a}

Step 3: <u>Multiply</u><u> </u><u>the </u><u>slopes </u><u>:</u><u>-</u><u> </u>

\sf\longrightarrow \dfrac{3}{2}\times \dfrac{-6}{a}= -1

Multiply ,

\sf\longrightarrow \dfrac{-9}{a}= -1

Multiply both sides by a ,

\sf\longrightarrow (-1)a = -9

Divide both sides by -1 ,

\sf\longrightarrow \boxed{\blue{\sf a = 9 }}

<u>Hence </u><u>the</u><u> </u><u>value</u><u> of</u><u> a</u><u> </u><u>is </u><u>9</u><u> </u><u>.</u>

8 0
3 years ago
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