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earnstyle [38]
2 years ago
12

What is .85 (85 repeating) as a fraction

Mathematics
1 answer:
mojhsa [17]2 years ago
6 0
.85 repeating as a fraction is
\frac{85}{100 }
You might be interested in
What is the square root of 5x^2 = 300
vesna_86 [32]

So, values of x are: x=2\sqrt{15},\,\,x=-2\sqrt{15}

Step-by-step explanation:

We need to find the square root of 5x^2 = 300

Writing in mathematical form:

5x^2=300

Divide both sides by 5

\frac{5x^2}{5}=\frac{300}{5}

x^2=60

Taking square root on both sides

\sqrt{x^2}=\sqrt{60}

x=\pm (\sqrt{2\times 2\times 3\times 5})

x=\pm (\sqrt{2^2 \times 3\times 5})

x=\pm (2\sqrt{3\times 5})

x=\pm (2\sqrt{15})

x=2\sqrt{15},\,\,x=-2\sqrt{15}

So, values of x are: x=2\sqrt{15},\,\,x=-2\sqrt{15}

Keywords: Square root

Learn more about square root at:

  • brainly.com/question/3511750
  • brainly.com/question/4034547

#learnwithBrainly

7 0
3 years ago
If your friend leaves your house at a speed of 8mph and two hours later you follow in your car at 40mph, how long will It be bef
dusya [7]

Answer:

  • 1/2 hour
  • 20 miles

Step-by-step explanation:

Your friend has a head start of (2 h)×(8 mi/h) = 16 mi.

When you leave, you gain on your friend at the rate of 40 mph - 8 mph = 32 mph. So, it will take ...

  (16 mi)/(32 mi/h) = 1/2 h

for you to reduce the distance between you to zero.

In that 1/2 hour, you have traveled ...

  (1/2 h)×(40 mi/h) = 20 mi

__

This is the same distance your friend has traveled in 2.5 hours at 8 mi/h.

3 0
3 years ago
What is the slope-intercept form of a linear equation? explain why this form is called the slope-intercept form?
Leviafan [203]
The slope-intercept form of a linear equation is y=mx+b. m being the slope (part one of name) and b being the y-intercept (part 2 of name).
5 0
3 years ago
What multiplies to 16 and adds to negative 12
Romashka-Z-Leto [24]
Factor 16 and see the - factor pairs and add them, see which add to -12
-1-16=-17 nope
-2-8=-10 nope
-4-4=-8
hmm


we will solve with math
xy=16
x+y=-12
minus  x both sides
y=-12-x
sub for y in other equation
x(-12-x)=16
-12x-x^2=16
add 12x+x^2 both sides
0=x^2+12x+16
use quadratic formula
if you have
ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}


0=x^2+12x+16
a=1
b=12
c=16

x=\frac{-12+/- \sqrt{12^{2}-4(1)(16) }}{2(1)}
x=\frac{-12+/- \sqrt{144-64 }}{2}
x=\frac{-12+/- \sqrt{80}}{2}
x=\frac{-12+/- 4\sqrt{5}}{2}
x=\frac{-6+/- 2\sqrt{5}
x=\frac{-6+ 2\sqrt{5} or \frac{-6- 2\sqrt{5}

aprox
x=-1.52786 or -10.4721

those are the numbers

the numbes are -1.52786 or -10.4721

6 0
3 years ago
Read 2 more answers
Point S is on line segment RT. Given RS = 4x – 10, ST = 2x – 10, and
borishaifa [10]

Answer:

The numerical length of RS is 22 units

Step-by-step explanation:

∵ Point S is on the line segment RT

→ <em>That means S divide RT into two parts RS and ST</em>

∴ RS + ST = RT

∵ RS = 4x - 10

∵ ST = 2x - 10

∵ RT = 4x - 4

→ <em>Substitute them in the statement above</em>

∴ 4x - 10 + 2x - 10 = 4x - 4

→ <em>Add the like terms in the left side</em>

∴ (4x + 2x) + (-10 + -10) = 4x - 4

∴ 6x + (-20) = 4x - 4

∴ 6x - 20 = 4x - 4

→ <em>Add 20 to both sides</em>

∴ 6x -20 + 20 = 4x - 4 + 20

∴ 6x = 4x + 16

→ <em>Subtract 4x from both sides</em>

∴ 6x - 4x = 4x - 4x + 16

∴ 2x = 16

→ <em>Divide both sides by 2 to find x</em>

∴ \frac{2x}{2}=\frac{16}{2}

∴ x = 8

→ <em>Substitute the value of x in Rs to find its length</em>

∵ RS = 4(8) - 10

∴ RS = 32 - 10

∴ RS = 22 units

The numerical length of RS is 22 units

3 0
2 years ago
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