ASAP pls help me giving brainliest

What is the range and domain of this graph?

DochEvi [55]

Answer:

Range: (-∞,∞)

Domain: (-∞,∞)

Step-by-step explanation:

Remember that if there are arrows that the function continues.

7 0

3 years ago

A computer can process the payroll for Hometel in 10 hours. An older back up computer needs 11 hours to

dem82 [27]

Both computers will do the job in 5 hours and 14 minutes.

Since a computer can process the payroll for Hometel in 10 hours, while an older back up computer needs 11 hours to process payroll, to determine how long would the job take if the two computers are both used to do the job, the following calculation should be performed:

X / 10 + X / 11 = 1
10X + 11X = 110
21X = 110
X = 110/21
X = 5.238
100 = 60
0.238 = X
0.238 x 60/100 = X
0.14 = X

Therefore, both computers will do the job in 5 hours and 14 minutes.

Learn more in brainly.com/question/14585276

4 0

2 years ago

Simplify 7x+4x+4-2x +8 what is the coefficient?what is its constant?

Virty [35]

Simplified: 9x+12

12 is the constant, 9 is the coefficient

5 0

3 years ago

Read 2 more answers

Suppose that wait times for customers at a grocery store cashier line are uniformly distributed between one minute and twelve mi

olchik [2.2K]

a) Mean: 6.5 min, variance: 10.1 min

b) 0.54 (54%)

c) 0.73 (73%)

d) 0.34

Step-by-step explanation:

a)

Here we can call X the variable indicating the waiting time for the customers:

X = waiting time

We are told that the waiting time is distributed uniformly between 1 and 12; this means that

$1\leq X \leq 12$

And the probability is equal for each value of X, so:

$p(X=1)=p(X=2)=....=p(X=12)$

The mean of a uniform distribution is given by:

$E[X]=\frac{b+a}{2}$

where a and b are the minimum and maximum values of the variable X. In this case,

a = 1

b = 12

So the mean value of X is

$E[X]=\frac{12+1}{2}=6.5$ (minutes)

The variance of a uniform distribution is given by:

$Var[X]=\frac{1}{12}(b-a)^2$

And substituting the values of this problem,

$Var[X]=\frac{1}{12}(12-1)^2=10.1$ (minutes)

b)

Since the distribution is uniform between 1 and 12, we can write the probability density function as

$f(x)=\frac{1}{b-a}$

The cumulative function gives the probability that the values of X is less than a certain value t:

$p(X$ (1)

In this case, we want to find the probability that the waiting time is less than 7 minutes, so

t = 7

We also have:

a = 1

b = 12

Therefore, calculating (1) and substituting, we find:

$p(X$

c)

The probability that a customer waits between four and twenty minutes can be rewritten as

$p(4$

This can be written as:

$p(4$ (1)

However, the probabilty of X>4 can be written as

$p(X>4)=1-p(X$

Also, we notice that

$p(X$ because the maximum value of X is 12; therefore, we can rewrite (1) as

$p(4$

We can calculate $p(X$ by using the same method as in part b:

$p(X$

So, we find

$p(4$

d)

In this part, we know that a customer waits for

X = k

minutes in line, and he receives a coupon worth

$0.2k^{\frac{1}{4}}$ dollars.

Here we want to find the mean of the coupon value.

Here therefore we have a new variables defined as

$Y=0.2X^{\frac{1}{4}}$

Given a variable with standard (between 0 and 1) uniform distribution X, the variable

$Y=X^n$

follows a beta distribution, with parameters $(\frac{1}{n},1)$ , and whose mean value is given by

$E[Y]=\frac{1/n}{1+\frac{1}{n}}$

In this case,

$n=\frac{1}{4}$

So the mean value of $X^{1/4}$ is

$E[X^{1/4}]=\frac{1/(1/4)}{1+\frac{1}{1/4}}=\frac{4}{1+4}=\frac{4}{5}=0.8$

However, our variable is distribution is non-standard, because its values are between 1 and 12, so the range is

$Min = 1^{1/4}=1\\Max =12^{1/4}=1.86$

So, the actual mean value of $X^{1/4}$ is

$E[X^{1/4}]=0.8\cdot (1.86-1)+1=1.69$

However, in the definition of Y we also have a factor 0.2; therefore, the mean value of Y is

$E[Y]=0.2E[X^{1/4}]=0.2\cdot 1.69 =0.34$

5 0

3 years ago

The first step in solving the equation 2+|4x−3|=7 is to isolate the absolute value expression. What is the first step to isolate

Natali [406]

Answer:

subtract 2 from both sides

Step-by-step explanation:

2+|4x-3|=7

|4x-3|+2=7

step 1:add -2 to both sides/subtract 2 from both sides (they are the same)

Step 2: Solve Absolute Value.

|4x−3|=5

We know either4x−3=5 or 4x−3=−5

4x−3=5(Possibility 1)

4x−3+3=5+3(Add 3 to both sides)

4x=8

4x /4=8/4

(Divide both sides by 4)

x=2

4x−3=−5 (Possibility 2)

4x−3+3=−5+3 (Add 3 to both sides)

4x=−2

4x /4 = −2 /4

(Divide both sides by 4)

x= −1 /2

Answer:

x=2 or x= −1 /2

3 0

3 years ago